Вопрос задан 30.04.2019 в 00:44. Предмет Химия. Спрашивает Simonkhyk Leonid.

По химии Вычеслите атомную массу (Mr) H3PO4,AL2(SO4)3.Пожалуйста и с ходом действия

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Отвечает Llorens Natasha.
Mr(H3PO4)=1×3+31+16×4=98
Mr(AL2(SO4)3=27×2+32×3+16×3+3(16×4)=54+96+192=342
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of Atomic Mass (Mr) for H3PO4

To calculate the atomic mass (Mr) of a compound, we need to determine the sum of the atomic masses of all the atoms present in the compound.

For H3PO4 (phosphoric acid), we have:

- 3 hydrogen atoms (H) - 1 phosphorus atom (P) - 4 oxygen atoms (O)

To calculate the atomic mass (Mr) of H3PO4, we can use the periodic table to find the atomic masses of each element and then multiply them by the number of atoms present in the compound.

The atomic masses of the elements are as follows: - Hydrogen (H): 1.00784 g/mol - Phosphorus (P): 30.97376 g/mol - Oxygen (O): 15.999 g/mol

Now, let's calculate the atomic mass (Mr) of H3PO4:

(3 * atomic mass of hydrogen) + atomic mass of phosphorus + (4 * atomic mass of oxygen)

= (3 * 1.00784 g/mol) + 30.97376 g/mol + (4 * 15.999 g/mol)

= 3.02352 g/mol + 30.97376 g/mol + 63.996 g/mol

= 97.99328 g/mol + 63.996 g/mol

= 161.98928 g/mol

Therefore, the atomic mass (Mr) of H3PO4 (phosphoric acid) is approximately 161.98928 g/mol.

Calculation of Atomic Mass (Mr) for AL2(SO4)3

For AL2(SO4)3 (aluminum sulfate), we have:

- 2 aluminum atoms (Al) - 3 sulfate ions (SO4)

To calculate the atomic mass (Mr) of AL2(SO4)3, we need to consider the atomic masses of each element and the number of atoms or ions present in the compound.

The atomic masses of the elements are as follows: - Aluminum (Al): 26.9815386 g/mol - Sulfur (S): 32.06 g/mol - Oxygen (O): 15.999 g/mol

Now, let's calculate the atomic mass (Mr) of AL2(SO4)3:

(2 * atomic mass of aluminum) + (3 * (atomic mass of sulfur + 4 * atomic mass of oxygen))

= (2 * 26.9815386 g/mol) + (3 * (32.06 g/mol + 4 * 15.999 g/mol))

= 53.9630772 g/mol + (3 * (32.06 g/mol + 63.996 g/mol))

= 53.9630772 g/mol + (3 * 96.056 g/mol)

= 53.9630772 g/mol + 288.168 g/mol

= 342.1310772 g/mol

Therefore, the atomic mass (Mr) of AL2(SO4)3 (aluminum sulfate) is approximately 342.1310772 g/mol.

Please note that the calculated atomic masses are approximate values and may vary slightly depending on the periodic table used and the isotopic composition of the elements.

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