Question

300 г гидроксида натрия нейтрализовали серной кислотой определить массу полученной соли

Answer 1

Жепа какает 
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Answer 2

Calculation of the Mass of the Obtained Salt

To determine the mass of the salt obtained from the neutralization of 300 g of sodium hydroxide (NaOH) with sulfuric acid (H2SO4), we need to consider the balanced chemical equation for the reaction:

2NaOH + H2SO4 -> Na2SO4 + 2H2O

From the balanced equation, we can see that 2 moles of sodium hydroxide react with 1 mole of sulfuric acid to produce 1 mole of sodium sulfate and 2 moles of water.

To calculate the mass of the obtained salt (sodium sulfate, Na2SO4), we need to determine the number of moles of sodium hydroxide used and then use the molar ratio from the balanced equation to find the number of moles of sodium sulfate produced.

1. Calculate the number of moles of sodium hydroxide (NaOH): - The molar mass of sodium hydroxide (NaOH) is 22.99 g/mol (sodium) + 16.00 g/mol (oxygen) + 1.01 g/mol (hydrogen) = 39.99 g/mol. - The number of moles of sodium hydroxide is calculated by dividing the mass of sodium hydroxide by its molar mass: Moles of NaOH = Mass of NaOH / Molar mass of NaOH = 300 g / 39.99 g/mol = 7.50 mol

2. Use the molar ratio from the balanced equation to find the number of moles of sodium sulfate (Na2SO4) produced: - From the balanced equation, we know that 2 moles of sodium hydroxide react to produce 1 mole of sodium sulfate. - Therefore, the number of moles of sodium sulfate is half the number of moles of sodium hydroxide used: Moles of Na2SO4 = 0.5 * Moles of NaOH = 0.5 * 7.50 mol = 3.75 mol

3. Calculate the mass of the obtained sodium sulfate (Na2SO4): - The molar mass of sodium sulfate (Na2SO4) is 22.99 g/mol (sodium) + 32.07 g/mol (sulfur) + (4 * 16.00 g/mol) (oxygen) = 142.04 g/mol. - The mass of sodium sulfate is calculated by multiplying the number of moles of sodium sulfate by its molar mass: Mass of Na2SO4 = Moles of Na2SO4 * Molar mass of Na2SO4 = 3.75 mol * 142.04 g/mol = 532.65 g

Therefore, the mass of the obtained sodium sulfate (Na2SO4) is approximately 532.65 grams.