Question

Сколько граммов KMnO4 следует взять для приготовления 1,5л 0,2н раствора? Срочно ,пожалуйста))))

Answer 1

M= CVM = 1,5*0,2* 158*1/5 = 9,48 г

Answer 2

Calculating the Amount of KMnO4 Needed

To calculate the amount of KMnO4 needed for preparing a 1.5L 0.2N solution, we can use the formula:

Normality (N) = (Weight of solute in grams / Equivalent weight of solute) / Volume of solution in liters

Given: - Volume of solution (V) = 1.5L - Normality (N) = 0.2N

We need to find the weight of KMnO4 required.

Calculation

Using the formula, we can rearrange it to solve for the weight of solute:

Weight of solute (in grams) = Normality (N) * Equivalent weight of solute * Volume of solution (in liters)

The equivalent weight of KMnO4 is 31 g/equivalent.

Plugging in the values: Weight of solute = 0.2N * 31 g/equivalent * 1.5L

Result

Calculating the above expression gives us the amount of KMnO4 needed to prepare the solution. Let's calculate it.