Question

Навеску соли массой 3 грамма растворили в воде массой - ? гр. . При этом образовался раствор с массовой долей соли 4,76% Найдите неизвестную величину

Answer 1

 ω=mвещества/mвещества+mводы отсюда
 ω(mвещества+mводы)=mвещества 0,0476(3+х)=3   0,0476х=2,8572 х=60г

Answer 2

Calculation of Unknown Quantity in Salt Solution

To find the unknown quantity in the salt solution, we need to use the given information about the mass of salt and the mass fraction of salt in the solution.

Given: - Mass of salt = 3 grams - Mass fraction of salt = 4.76%

Let's denote the mass of water in the solution as x grams.

To calculate the mass of water, we can use the following equation:

Mass of salt / (Mass of salt + Mass of water) = Mass fraction of salt / 100

Substituting the given values:

3 / (3 + x) = 4.76 / 100

To solve for x, we can cross-multiply and solve the equation:

3 * 100 = 4.76 * (3 + x)

Simplifying the equation:

300 = 14.28 + 4.76x

4.76x = 300 - 14.28

4.76x = 285.72

x = 285.72 / 4.76

x ≈ 60 grams

Therefore, the mass of water in the solution is approximately 60 grams.