Question

При полном сгорании 3,8 г вещества образовалось 2,2 г оксида углерода(4) и 6,4 г оксида серы (4) . Найдите простейшую формулу вещества!!! Ответ CS2. Помогите с решением, Распишите пожалуйста!!!!

Answer 1

n(CO2)=2,2г:44г/моль=0,05моль;n(C)=0,05моль;m(C)=0,05мольx12г/моль=0,6г;

n(SO2)=6,4г:64г/моль=0,1моль;n(S)=0,1моль; m(S)=0,1мольx32г/моль=3,2г;

 0,6г+3,2г=3,8г-след.,исходное в-во состояло только из 2-ух хим.элементов:С и S.

n(C):n(S)=0,05:0,1

                     1:2

                                      Ответ:С1S2(CS2)-сероуглерод!

Я понятно объяснила?

Answer 2

Problem Analysis

We are given that 3.8 g of a substance undergoes complete combustion and forms 2.2 g of carbon dioxide (CO2) and 6.4 g of sulfur dioxide (SO2). We need to determine the simplest formula of the substance.

Solution

To find the simplest formula of the substance, we need to determine the molar ratios of the elements present in the compound.

Let's start by calculating the number of moles of carbon dioxide (CO2) and sulfur dioxide (SO2) formed.

The molar mass of carbon dioxide (CO2) is 44.01 g/mol, and the molar mass of sulfur dioxide (SO2) is 64.06 g/mol.

The number of moles of carbon dioxide (CO2) can be calculated using the formula:

moles = mass / molar mass

For carbon dioxide (CO2): moles of CO2 = 2.2 g / 44.01 g/mol = 0.05 mol

For sulfur dioxide (SO2): moles of SO2 = 6.4 g / 64.06 g/mol = 0.1 mol

Now, we need to find the simplest whole number ratio between the moles of carbon dioxide (CO2) and sulfur dioxide (SO2).

Dividing the moles of carbon dioxide (CO2) by the smaller number of moles (0.05 mol), we get:

moles of CO2 / smaller number of moles = 0.05 mol / 0.05 mol = 1

Dividing the moles of sulfur dioxide (SO2) by the smaller number of moles (0.05 mol), we get:

moles of SO2 / smaller number of moles = 0.1 mol / 0.05 mol = 2

The ratio between the moles of carbon dioxide (CO2) and sulfur dioxide (SO2) is 1:2.

This means that the simplest formula of the substance is CS2, where C represents carbon and S represents sulfur.

Therefore, the simplest formula of the substance is CS2.

Conclusion

The simplest formula of the substance, given that 3.8 g of the substance forms 2.2 g of carbon dioxide (CO2) and 6.4 g of sulfur dioxide (SO2) upon complete combustion, is CS2.