Question

Подпишите не достающие степени окисления плиз HnO2 CH4 AI2(SO4)3 CaCO3 K2MnO4 K2So3

Answer 1

Нужно расставить степени окисления? 
HnО2 ? это H2O2, если да, то c.0(H)=+1, c.o(O)=-1
CH4 c.o(C)=-4, c.o(h)=+1
Al2(so4)3, c.o(Al) = +3, c.o(S) = +6. c.o(O) = -2
CaCO3, c.o (Ca)=+2, c.о(С)=+6, c.o(O)=-2
K2MnO4, c.o. (K)=+1, c.o (Mn)=+6, c.o(O)=-2
K2so3, c.o(K)=+1, c.o(S)=+4, c.o( o) = -2
c.o. - это степень окисления

Answer 2

Oxidation States of the Given Compounds

Here are the oxidation states of the given compounds:

1. HnO2: - The oxidation state of hydrogen (H) is usually +1, except when it is bonded to a metal, in which case it can be -1. - The oxidation state of oxygen (O) is typically -2, except in peroxides where it is -1. - Since the compound is not specified, we can assume it is a peroxide. Therefore, the oxidation state of oxygen in HnO2 is -1. - To find the oxidation state of hydrogen, we can use the equation: 2x + (-1) = 0, where x is the oxidation state of hydrogen. - Solving the equation, we find that the oxidation state of hydrogen in HnO2 is +1.

2. CH4: - The oxidation state of hydrogen (H) is usually +1, except when it is bonded to a metal, in which case it can be -1. - The oxidation state of carbon (C) is typically +4, except in certain compounds where it can be different. - In CH4, since hydrogen is bonded to carbon, the oxidation state of hydrogen is +1. - To find the oxidation state of carbon, we can use the equation: 4(+1) + x = 0, where x is the oxidation state of carbon. - Solving the equation, we find that the oxidation state of carbon in CH4 is -4.

3. AI2(SO4)3: - The oxidation state of aluminum (Al) is typically +3. - The oxidation state of oxygen (O) is typically -2, except in peroxides where it is -1. - The oxidation state of sulfur (S) in sulfate (SO4) is +6. - To find the oxidation state of sulfur, we can use the equation: 4(-2) + x = -2, where x is the oxidation state of sulfur. - Solving the equation, we find that the oxidation state of sulfur in sulfate is +6. - To find the oxidation state of aluminum, we can use the equation: 2(+3) + 3(-2) = 0, where x is the oxidation state of aluminum. - Solving the equation, we find that the oxidation state of aluminum in AI2(SO4)3 is +3.

4. CaCO3: - The oxidation state of calcium (Ca) is typically +2. - The oxidation state of oxygen (O) is typically -2, except in peroxides where it is -1. - The oxidation state of carbon (C) in carbonate (CO3) is +4. - To find the oxidation state of carbon, we can use the equation: 3(-2) + x = -2, where x is the oxidation state of carbon. - Solving the equation, we find that the oxidation state of carbon in carbonate is +4. - To find the oxidation state of calcium, we can use the equation: (+2) + 3(-2) = 0, where x is the oxidation state of calcium. - Solving the equation, we find that the oxidation state of calcium in CaCO3 is +2.

5. K2MnO4: - The oxidation state of potassium (K) is typically +1. - The oxidation state of oxygen (O) is typically -2, except in peroxides where it is -1. - The oxidation state of manganese (Mn) in permanganate (MnO4) is +7. - To find the oxidation state of manganese, we can use the equation: 4(-2) + x = -1, where x is the oxidation state of manganese. - Solving the equation, we find that the oxidation state of manganese in permanganate is +7. - To find the oxidation state of potassium, we can use the equation: 2(+1) + 4(-2) = 0, where x is the oxidation state of potassium. - Solving the equation, we find that the oxidation state of potassium in K2MnO4 is +1.

6. K2SO3: - The oxidation state of potassium (K) is typically +1. - The oxidation state of oxygen (O) is typically -2, except in peroxides where it is -1. - The oxidation state of sulfur (S) in sulfite (SO3) is +4. - To find the oxidation state of sulfur, we can use the equation: 3(-2) + x = -2,