Question

Осуществите превращение: K -- K2O -- KOH -- (ниже Fe(OH)3) -- K3PO4 -- Ca3(PO4)2

Answer 1

1) 4К+О2=2К2О;

2) K2O + H2O = 2KOH;

3) H3PO4+3KOH=K3PO4+3H2O;

4) 2K3PO4 + 3CaCl2 = Ca3(PO4)2 + 6KCl;

5) 3KOH + Fe(NO3)3 = 3KNO3 + Fe(OH)3

Answer 2

I can help you with your chemistry question. Here is the detailed answer:

The transformation consists of several steps:

1. K + O2 -> K2O This is a synthesis reaction, where potassium metal reacts with oxygen gas to form potassium oxide. The balanced equation is:

$$4K + O_2 \rightarrow 2K_2O$$

2. K2O + H2O -> KOH This is a decomposition reaction, where potassium oxide reacts with water to form potassium hydroxide. The balanced equation is:

$$K_2O + H_2O \rightarrow 2KOH$$

3. KOH + Fe(OH)3 -> KFeO2 + H2O This is a double displacement reaction, where potassium hydroxide reacts with iron(III) hydroxide to form potassium ferrate(II) and water. The balanced equation is:

$$2KOH + Fe(OH)_3 \rightarrow K_2FeO_2 + 2H_2O$$

4. KFeO2 + H3PO4 -> K3PO4 + FePO4 This is another double displacement reaction, where potassium ferrate(II) reacts with phosphoric acid to form potassium phosphate and iron(II) phosphate. The balanced equation is:

$$3K_2FeO_2 + 2H_3PO_4 \rightarrow 2K_3PO_4 + Fe_3(PO_4)_2$$

5. Fe3(PO4)2 + Ca(OH)2 -> Ca3(PO4)2 + Fe(OH)2 This is the final double displacement reaction, where iron(II) phosphate reacts with calcium hydroxide to form calcium phosphate and iron(II) hydroxide. The balanced equation is:

$$Fe_3(PO_4)_2 + 6Ca(OH)_2 \rightarrow 3Ca_3(PO_4)_2 + 2Fe(OH)_2$$

I hope this helps you understand the transformation. If you have any more questions, feel free to ask me.Ответь+подробно.+Осуществите+превращение:+K+--+K2O+--+KOH+--+(ниже+Fe(OH)3)+--+K3PO4+--+Ca3(PO4)2