Вопрос задан 28.04.2019 в 01:53. Предмет Химия. Спрашивает Баскаль Елизавета.

Сколько литров углекислого газа необходимо для реакции с 80г гидроксида натрия.

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Отвечает Гайко Діма.
2 NaOH + CO2 = Na2CO3 + H2O
n(NaOH) = 80 г / (23+16+1) г/моль= 2 моль
По уравнению n(NaOH)=2n(CO2), n(CO2)=1/2 n(NaOH)=1/2 * 2=1 моль
V(CO2)=1 моль * 22,4 л/моль = 22,4 л  
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of Carbon Dioxide Required for the Reaction

To calculate the amount of carbon dioxide (CO2) required for the reaction with 80g of sodium hydroxide (NaOH), we can use the stoichiometry of the reaction between sodium hydroxide and carbon dioxide.

The balanced chemical equation for the reaction is: 2 NaOH + CO2 → Na2CO3 + H2O

According to the stoichiometry of the reaction, 2 moles of sodium hydroxide react with 1 mole of carbon dioxide.

Calculation Steps

1. Calculate the moles of sodium hydroxide (NaOH) from the given mass of 80g. 2. Use the mole ratio from the balanced chemical equation to find the moles of carbon dioxide required. 3. Convert the moles of carbon dioxide to liters using the ideal gas law.

Calculation Steps Explained

1. Calculate the moles of sodium hydroxide (NaOH): - The molar mass of NaOH is 22.99 (Na) + 15.999 (O) + 1.008 (H) = 39.997 g/mol. - Moles of NaOH = Mass of NaOH / Molar mass of NaOH - Moles of NaOH = 80g / 39.997 g/mol

The moles of NaOH can be calculated using the molar mass of sodium hydroxide.

Calculation: Moles of NaOH = 80g / 39.997 g/mol = 2.000 moles of NaOH

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2. Use the mole ratio to find the moles of carbon dioxide: - According to the balanced chemical equation, 2 moles of NaOH react with 1 mole of CO2. - Moles of CO2 = Moles of NaOH / 2

The mole ratio from the balanced chemical equation is used to find the moles of carbon dioxide required.

Calculation: Moles of CO2 = 2.000 moles of NaOH / 2 = 1.000 moles of CO2

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3. Convert the moles of carbon dioxide to liters using the ideal gas law: - The ideal gas law is PV = nRT, where P is pressure, V is volume, n is moles, R is the gas constant, and T is temperature. - At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters.

The moles of carbon dioxide can be converted to liters using the ideal gas law at STP.

Calculation: Volume of CO2 = 1.000 moles of CO2 * 22.4 L/mol = 22.4 liters of CO2

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Conclusion

The reaction of 80g of sodium hydroxide with carbon dioxide requires approximately 22.4 liters of carbon dioxide at standard temperature and pressure (STP).

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