Question

Яка молярна концентрація одержаного розчину CuSO4, якщо 40г. його розчину в 500мл води?

Answer 1

M(розч) = 500 мл*1г/мл + 40 г = 540 г
ω(СuSO4) = 40 г/540 г = 0,074 или 7,4%
ρ(розч.CuSO4) = 1 г/мл
V(poзч) = 540 г/1 г/мл = 540 мл = 0,54 л
M(CuSO4) = 160 г/моль
n(CuSO4) = 40 г/160 г/моль = 0,25 моль
См= 0,25 моль/0,54 л = 0,46 моль/л
Відповідь: 0,46 моль/л

Answer 2

Molar Concentration of CuSO4 Solution

To calculate the molar concentration of the CuSO4 solution, we can use the formula:

Molar concentration (M) = (moles of solute) / (volume of solution in liters)

First, we need to find the moles of CuSO4 in the given mass, and then we can calculate the molar concentration using the volume of the solution.

Finding Moles of CuSO4

The molar mass of CuSO4 can be calculated as follows:

Molar mass of CuSO4 = atomic mass of Cu + atomic mass of S + 4 * atomic mass of O

Using the atomic masses of Cu (63.55 g/mol), S (32.07 g/mol), and O (16.00 g/mol), we can calculate the molar mass of CuSO4.

Next, we can use the given mass of CuSO4 (40g) to find the moles of CuSO4 using the molar mass.

Calculating Molar Concentration

Once we have the moles of CuSO4, we can use the formula mentioned earlier to calculate the molar concentration of the solution.

Let's proceed with these calculations.