Question

Определите количество вещества 96,3 г гидроксида железа (III). Fe(OH)3

Answer 1

Рассчитаем количество вещества  Fe(OH)3  

Answer 2

I can answer your question in Russian. The amount of substance of 96.3 g of iron (III) hydroxide is calculated by dividing the mass by the molar mass. The molar mass of Fe(OH)3 is 106.87 g/mol, according to [Wikipedia](https://ru.wikipedia.org/wiki/%D0%93%D0%B8%D0%B4%D1%80%D0%BE%D0%BA%D1%81%D0%B8%D0%B4_%D0%B6%D0%B5%D0%BB%D0%B5%D0%B7%D0%B0%28III%29). Therefore, the amount of substance is:

$$n = \frac{m}{M} = \frac{96.3}{106.87} = 0.901 \text{ mol}$$

I hope this helps. If you have any other questions, feel free to ask me.