Question

Объясните, почему в приведенных ниже реакциях продукты восстановления окислителя разные. 2KBr + 2H2SO4 (K) = Br2 +SO2+ K2SO4 + 2H2O 8KI + 5H2SO4 (K) = 4I2 +H2S+ 4K2SO4 + 4H2O

Answer 1

Потому что бром не такой сильный восстановитель как йод. Йод является одним из сильнейших восстановителей . Поэтому йод восстанавливает серу до СО -2 , а бром до СО +4

Answer 2

Explanation of Different Oxidation Reactions

In the given reactions, the products of the oxidation of the reactants are different. Let's analyze each reaction separately to understand why the products of the oxidation are different.

1. 2KBr + 2H2SO4 → Br2 + SO2 + K2SO4 + 2H2O 2. 8KI + 5H2SO4 → 4I2 + H2S + 4K2SO4 + 4H2O

Reaction 1: 2KBr + 2H2SO4 → Br2 + SO2 + K2SO4 + 2H2O

This reaction involves the oxidation of potassium bromide (KBr) and sulfuric acid (H2SO4). The products of this reaction are bromine (Br2), sulfur dioxide (SO2), potassium sulfate (K2SO4), and water (H2O).

Reaction 2: 8KI + 5H2SO4 → 4I2 + H2S + 4K2SO4 + 4H2O

In this reaction, the oxidation of potassium iodide (KI) and sulfuric acid (H2SO4) occurs. The products of this reaction are iodine (I2), hydrogen sulfide (H2S), potassium sulfate (K2SO4), and water (H2O).

The different products of the oxidation reactions are due to the different starting materials (KBr and KI) and the specific properties of the elements involved (bromine and iodine) in each reaction. The specific chemical properties of the elements and compounds involved determine the products of the oxidation reactions.

In summary, the different products of the oxidation reactions are a result of the specific properties of the reactants and the elements involved in each reaction.