Question

Какая масса воды потребунтся для электролиза,чтобы получить 112 л (н.у) кислорода?

Answer 1

Решение во вложении...................................

Answer 2

2Н₂О --электролиз-----> 2Н₂ + О₂

1) Определим массу выделившегося кислорода
M(O₂) = 16 * 2 = 32 г/моль 
m(O₂) = 32 * 112 : 22,4 = 160 г

2) Определим массу воды, необходимую для электролиза
М(Н₂О) = 1 * 2 + 16 = 18 г/моль
m(Н₂О) = (18 * 2 * 160) : (32 * 1) = 180 г

Answer 3

Calculating Water Mass Required for Electrolysis to Obtain 112 Liters of Oxygen

To calculate the mass of water required for electrolysis to obtain 112 liters of oxygen at standard temperature and pressure (STP), we can use the following formula:

2H2O → 2H2 + O2

According to the stoichiometry of the reaction, 2 moles of water produce 1 mole of oxygen gas. From Avogadro's law, 1 mole of any gas at STP occupies 22.4 liters. Therefore, 112 liters of oxygen gas at STP is equivalent to 112/22.4 = 5 moles of oxygen gas.

Now, let's calculate the mass of water required using this information.

Calculation

Using the molar mass of water (H2O) which is approximately 18 grams per mole, we can calculate the mass of water required.

1 mole of water = 18 grams 5 moles of water = 18 * 5 = 90 grams

Therefore, approximately 90 grams of water would be required for electrolysis to obtain 112 liters of oxygen at STP.

Cited Sources

1. Source 5: "112 2, . . 70%. = ? ? 120." 2. Source 6: "112 2, ? ? . . 70 %. = 120."