Question

Сколько мл газа выделится (при н.у.), если обработать 1,5г цинка HCl (конц)?

Answer 1

Zn + 2HCl= ZnCl2 + H2
M(Zn)=65 г\моль
n(Zn)= m\M= 1,5\65=0,023 моль
т опо уравнению реакции колво моль H2 = колву моль Zn
n(H2)=0,023 моль
V(H2)= 0,023*22,4=0,515 л= 515 мл
ОТвет 515 мл

Answer 2

Gas Production from Zinc and HCl Reaction

When 1.5g of zinc is treated with hydrochloric acid (HCl) at standard conditions, the amount of gas produced can be calculated using the stoichiometry of the reaction.

The balanced chemical equation for the reaction between zinc and hydrochloric acid is:

Zn + 2HCl → ZnCl2 + H2

From the balanced equation, it is clear that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

Using the molar mass of zinc (Zn) and hydrochloric acid (HCl), we can calculate the amount of gas produced.

The molar mass of zinc (Zn) is approximately 65.38 g/mol. The molar mass of hydrochloric acid (HCl) is approximately 36.46 g/mol.

Calculation

1. Calculate the number of moles of zinc: - Number of moles = Mass / Molar mass - Number of moles = 1.5g / 65.38 g/mol - Number of moles ≈ 0.02296 moles

2. Using the stoichiometry of the reaction, we find the moles of hydrogen gas produced: - According to the balanced equation, 1 mole of zinc produces 1 mole of hydrogen gas. - Therefore, the moles of hydrogen gas produced ≈ 0.02296 moles

3. Convert moles of hydrogen gas to volume at standard conditions: - At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. - Volume of gas produced ≈ 0.02296 moles * 22.4 L/mol - Volume of gas produced ≈ 0.514144 L

Conclusion

When 1.5g of zinc is treated with hydrochloric acid at standard conditions, approximately 0.514144 liters of gas (H2) will be produced.