Question

Найти массу глюкозы выработанной при фотосинтезе 80 л газа

Answer 1

                                 х г           80 л
6СO2 + 6H2O = C6H12O6 + 6O2
                               180 г        134,4 л
х:180=80:134,4
х= 107,14 г

Answer 2

Calculation of Glucose Produced in Photosynthesis

To calculate the mass of glucose produced in photosynthesis, we need to consider the amount of gas produced as well. The given information states that 80 liters of gas is produced. However, it does not specify the type of gas. To proceed with the calculation, we will assume that the gas produced is oxygen (O2), which is a common byproduct of photosynthesis.

The equation for photosynthesis is as follows:

6CO2 + 6H2O + light energy → C6H12O6 + 6O2

From this equation, we can see that for every molecule of glucose (C6H12O6) produced, six molecules of oxygen (O2) are also produced. Therefore, the molar ratio of glucose to oxygen is 1:6.

To calculate the mass of glucose produced, we need to know the molar mass of glucose. The molar mass of glucose (C6H12O6) is approximately 180.16 g/mol.

Now, let's calculate the mass of glucose produced:

1. Convert the volume of gas (80 liters) to moles of oxygen (O2) using the ideal gas law. The molar volume of a gas at standard temperature and pressure (STP) is 22.4 liters/mol.

80 liters O2 * (1 mol O2 / 22.4 liters O2) = 3.57 moles O2

2. Since the molar ratio of glucose to oxygen is 1:6, we can calculate the moles of glucose produced:

3.57 moles O2 * (1 mole glucose / 6 moles O2) = 0.595 moles glucose

3. Finally, calculate the mass of glucose produced:

0.595 moles glucose * 180.16 g/mol = 107.2 grams of glucose

Therefore, approximately 107.2 grams of glucose would be produced in photosynthesis if 80 liters of gas (assumed to be oxygen) were produced.

Please note that the given information does not specify the conditions under which photosynthesis occurred (e.g., light intensity, temperature, etc.). These conditions can affect the efficiency of photosynthesis and the amount of glucose produced.