Question

Розставити коефіцієнти, розібрати реакцію методом електронного балансу Al+HNO3=Al(NO3)3+NO2+H2O

Answer 1

Al + 6HNO3 → Al(NO3)3 + 3NO2 + 3H2O
al°--al+³-пр.ок-ия.вос-тель
n+5--n+4-пр.вос-ияок-тель

Answer 2

Reaction and Balancing Equation

The given chemical equation is: Al + HNO3 = Al(NO3)3 + NO2 + H2O.

To balance this equation using the electron balance method, we need to ensure that the number of electrons lost in the oxidation half-reaction is equal to the number of electrons gained in the reduction half-reaction.

Oxidation Half-Reaction

The oxidation half-reaction involves the element that is being oxidized. In this case, aluminum (Al) is being oxidized from an oxidation state of 0 to +3 in Al(NO3)3.

The balanced oxidation half-reaction is: Al → Al^3+ + 3e^-

Reduction Half-Reaction

The reduction half-reaction involves the element that is being reduced. In this case, nitrogen (N) in nitric acid (HNO3) is being reduced from an oxidation state of +5 to +4 in NO2.

The balanced reduction half-reaction is: HNO3 + 2e^- → NO2 + 2H^+

Balancing the Equation

To balance the equation, we need to multiply the oxidation half-reaction by 2 and the reduction half-reaction by 3 to ensure that the number of electrons lost in the oxidation half-reaction is equal to the number of electrons gained in the reduction half-reaction.

The balanced equation is: 2Al + 6HNO3 → 2Al(NO3)3 + 3NO2 + 3H2O

Summary

The balanced equation for the reaction between aluminum (Al) and nitric acid (HNO3) is: 2Al + 6HNO3 → 2Al(NO3)3 + 3NO2 + 3H2O

Please note that the above explanation and balanced equation were derived using the electron balance method.