Question

Вода массой 180 г при 300°С прореагировала с избытком кокса. В полученной равновесной смеси объемная доля водорода 25%. Какую массу Fe3O4 можно восстановить полученным водородом? Ответ: 193 г

Answer 1

Решение в фото..........:

Answer 2

Problem Analysis

We are given that 180 g of water reacts with an excess of coke at 300°C, resulting in an equilibrium mixture with a volume fraction of hydrogen equal to 25%. We need to determine the mass of Fe3O4 that can be reduced by the hydrogen produced.

Solution

To solve this problem, we need to use the stoichiometry of the reaction between water and coke. The balanced equation for the reaction is:

C + H2O -> CO + H2

From the equation, we can see that 1 mole of water produces 1 mole of hydrogen. We are given the volume fraction of hydrogen in the equilibrium mixture, which is 25%. This means that 25% of the total volume of the mixture is hydrogen.

To find the mass of Fe3O4 that can be reduced by the hydrogen, we need to determine the moles of hydrogen produced. We can then use the stoichiometry of the reaction between Fe3O4 and hydrogen to find the mass of Fe3O4.

Let's calculate the moles of hydrogen produced:

1. Calculate the moles of water: - Given mass of water = 180 g - Molar mass of water (H2O) = 18 g/mol - Moles of water = (mass of water) / (molar mass of water)

2. Calculate the moles of hydrogen: - Moles of hydrogen = (moles of water) * (moles of hydrogen per mole of water)

3. Calculate the mass of Fe3O4: - Given volume fraction of hydrogen = 25% - Assume the total volume of the equilibrium mixture is 1 L (for simplicity) - Moles of hydrogen = (volume fraction of hydrogen) * (total volume of mixture) * (molar mass of hydrogen) / (molar volume of gas at STP) - Moles of Fe3O4 = (moles of hydrogen) * (moles of Fe3O4 per mole of hydrogen) - Mass of Fe3O4 = (moles of Fe3O4) * (molar mass of Fe3O4)

Let's calculate the values step by step:

1. Calculate the moles of water: - Moles of water = 180 g / 18 g/mol = 10 mol

2. Calculate the moles of hydrogen: - Moles of hydrogen = 10 mol * 1 mol/mol = 10 mol

3. Calculate the mass of Fe3O4: - Moles of hydrogen = 0.25 * 1 L * (2 g/mol) / (22.4 L/mol) = 0.2232 mol - Moles of Fe3O4 = 0.2232 mol * (1 mol Fe3O4 / 3 mol H2) = 0.0744 mol - Mass of Fe3O4 = 0.0744 mol * (232.8 g/mol) = 17.3 g

Therefore, the mass of Fe3O4 that can be reduced by the hydrogen is approximately 17.3 g.

Answer

The mass of Fe3O4 that can be reduced by the hydrogen produced is approximately 17.3 g.