Question

Реакция ионного обмена, идущая до конца A)NaOH + HCl → NaCl + H2OB)NaNO3 + KCl → NaCl + KNO3C)Zn + 2HCl → ZnCl2 + H2D)Na2CO3 + 2KOH → K2CO3 + 2NaOH

Answer 1

Ответ : А
Реакции ионного обмена идут до конца ,если выделяется газ,образуется вода или выпадает осадок.

Answer 2

Reaction 1: NaOH + HCl → NaCl + H2O

The reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) is a classic example of an acid-base reaction. In this reaction, the sodium hydroxide, which is a strong base, reacts with hydrochloric acid, which is a strong acid, to form sodium chloride (NaCl) and water (H2O). This reaction is also known as a neutralization reaction because the acidic and basic properties of the reactants are neutralized.

The balanced chemical equation for this reaction is:

2NaOH + 2HCl → 2NaCl + 2H2O

This equation shows that for every 2 moles of sodium hydroxide and hydrochloric acid, 2 moles of sodium chloride and water are produced.

Reaction 2: NaNO3 + KCl → NaCl + KNO3

The reaction between sodium nitrate (NaNO3) and potassium chloride (KCl) is an example of a double displacement reaction. In this reaction, the sodium nitrate reacts with potassium chloride to form sodium chloride and potassium nitrate. Double displacement reactions involve the exchange of ions between two compounds.

The balanced chemical equation for this reaction is:

NaNO3 + KCl → NaCl + KNO3

This equation shows that for every 1 mole of sodium nitrate and potassium chloride, 1 mole of sodium chloride and potassium nitrate are produced.

Reaction 3: Zn + 2HCl → ZnCl2 + H2

The reaction between zinc (Zn) and hydrochloric acid (HCl) is an example of a single displacement reaction. In this reaction, the zinc reacts with hydrochloric acid to form zinc chloride and hydrogen gas. Single displacement reactions involve the displacement of one element by another in a compound.

The balanced chemical equation for this reaction is:

Zn + 2HCl → ZnCl2 + H2

This equation shows that for every 1 mole of zinc and 2 moles of hydrochloric acid, 1 mole of zinc chloride and 1 mole of hydrogen gas are produced.

Reaction 4: Na2CO3 + 2KOH → K2CO3 + 2NaOH

The reaction between sodium carbonate (Na2CO3) and potassium hydroxide (KOH) is an example of a double displacement reaction. In this reaction, the sodium carbonate reacts with potassium hydroxide to form potassium carbonate and sodium hydroxide.

The balanced chemical equation for this reaction is:

Na2CO3 + 2KOH → K2CO3 + 2NaOH

This equation shows that for every 1 mole of sodium carbonate and 2 moles of potassium hydroxide, 1 mole of potassium carbonate and 2 moles of sodium hydroxide are produced.

Please note that the reactions mentioned above are simplified representations of the chemical reactions. In reality, there may be additional factors or conditions that can affect the reactions.