Question

При анализе вещества нашли, что в его состав входят 40% углерода, 6,66% водорода и 53,34% кислорода. Найдите молекулярную формулу и назовите это вещество, если известно, что плотность его паров по воздуху равна 2,07.

Answer 1

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Answer 2

Molecular Formula and Name of the Substance

Based on the given information, the substance consists of 40% carbon, 6.66% hydrogen, and 53.34% oxygen. To determine the molecular formula and name of the substance, we need to calculate the empirical formula first.

To calculate the empirical formula, we assume we have 100 grams of the substance. From the given percentages, we can determine the number of moles of each element:

- Carbon (C): 40 grams (40% of 100 grams) of carbon is equal to 3.33 moles of carbon. - Hydrogen (H): 6.66 grams (6.66% of 100 grams) of hydrogen is equal to 6.61 moles of hydrogen. - Oxygen (O): 53.34 grams (53.34% of 100 grams) of oxygen is equal to 3.33 moles of oxygen.

Next, we need to find the simplest whole-number ratio of the elements. Dividing the number of moles of each element by the smallest number of moles (in this case, 3.33 moles), we get:

- Carbon: 3.33 moles / 3.33 moles = 1 mole - Hydrogen: 6.61 moles / 3.33 moles ≈ 1.98 moles (rounded to 2 moles) - Oxygen: 3.33 moles / 3.33 moles = 1 mole

Therefore, the empirical formula of the substance is CH2O.

To determine the molecular formula, we need to know the molar mass of the substance. Unfortunately, the molar mass is not provided in the given information or search results. Without the molar mass, we cannot determine the molecular formula or the specific name of the substance.

Please provide the molar mass of the substance, or if you have any other questions, feel free to ask!