Question

Составьте уравнения следующих превращений:Na---Na2O2---Na2O---NaOH---Na2SO4---NaCl---NaДля уравнения реакции 2 составьте схему электронного баланса.Для уравнения 5 напишите сокращенное ионно-молекулярное уравнение.

Answer 1

2Na + O2 = Na2O2

2Na2O2 + S = Na2SO3 + Na2O

Na2O + H2O --> 2NaOH

2NaOH + H2SO4 --> Na2SO4 + 2H2O

BaCl2+Na2SO4  --> BaSO4+2NaCl

Полная

форма:            Ba2+ + 2Cl− + 2Na+ + SO42− = BaSO4↓ + 2Na+ + 2Cl−

 

Краткая

форма:            Ba2+ + SO42− = BaSO4↓

 

 

2NaCl --> 2Na + Cl2

 

 

 

 

 

 

 

Answer 2

Equations for the Given Transformations:

1. Na → Na2O2: - The transformation involves the formation of sodium peroxide (Na2O2). - The balanced equation for this transformation is: 2Na + O2 → Na2O2 [[1]].

2. Na2O2 → Na2O: - The transformation involves the decomposition of sodium peroxide (Na2O2) into sodium oxide (Na2O) and oxygen gas (O2). - The balanced equation for this transformation is: 2Na2O2 → 2Na2O + O2 [[2]].

3. Na2O → NaOH: - The transformation involves the reaction of sodium oxide (Na2O) with water (H2O) to form sodium hydroxide (NaOH). - The balanced equation for this transformation is: Na2O + H2O → 2NaOH [[3]].

4. NaOH → Na2SO4: - The transformation involves the reaction of sodium hydroxide (NaOH) with sulfuric acid (H2SO4) to form sodium sulfate (Na2SO4) and water (H2O). - The balanced equation for this transformation is: 2NaOH + H2SO4 → Na2SO4 + 2H2O [[4]].

5. Na2SO4 → NaCl: - The transformation involves the reaction of sodium sulfate (Na2SO4) with hydrochloric acid (HCl) to form sodium chloride (NaCl) and sulfuric acid (H2SO4). - The balanced equation for this transformation is: Na2SO4 + 2HCl → 2NaCl + H2SO4 [[5]].

6. NaCl → Na: - The transformation involves the electrolysis of sodium chloride (NaCl) to obtain sodium metal (Na) and chlorine gas (Cl2). - The balanced equation for this transformation is: 2NaCl → 2Na + Cl2 [[6]].

Electron Balance for the Reaction 2:

The reaction 2 involves the transformation of sodium peroxide (Na2O2) into sodium oxide (Na2O) and oxygen gas (O2). To balance the electron transfer, we need to ensure that the total number of electrons gained is equal to the total number of electrons lost.

The balanced electron transfer for the reaction 2 can be represented as follows:

2Na2O2 → 2Na2O + O2

In this reaction, each sodium atom loses one electron, resulting in a total loss of 4 electrons. On the other hand, each oxygen atom gains two electrons, resulting in a total gain of 8 electrons. Therefore, the electron balance is achieved in this reaction.

Ionic-Molecular Equation for the Reaction 5:

The reaction 5 involves the reaction of sodium sulfate (Na2SO4) with hydrochloric acid (HCl) to form sodium chloride (NaCl) and sulfuric acid (H2SO4).

The ionic equation for this reaction can be written as follows:

Na2SO4 + 2HCl → 2NaCl + H2SO4

In this equation, the sodium sulfate dissociates into sodium ions (Na+) and sulfate ions (SO4^2-), while hydrochloric acid dissociates into hydrogen ions (H+) and chloride ions (Cl-). The sodium ions and chloride ions then combine to form sodium chloride, while the hydrogen ions and sulfate ions combine to form sulfuric acid.

The molecular equation for this reaction is the same as the ionic equation:

Na2SO4 + 2HCl → 2NaCl + H2SO4

This equation represents the overall reaction between the compounds involved.

I hope this helps! Let me know if you have any further questions.