Question

Число электронов, отдаваемых одним атомом металла в реакции, схема которой Al+S--> (при нагревании)

Answer 1

2AI+3S=Al2S3
AI(0)-3e=Al(+3)
S(0)+2e=S(-2)
Атом алюминия отдаёт 3 электрона

Answer 2

Reaction of Aluminum Sulfide

The reaction of aluminum sulfide (AlS) when heated is:

AlS (solid) → Al (solid) + S (gas)

In this reaction, one aluminum atom donates one electron to form the gaseous sulfur atom. Aluminum atoms have 3 valence electrons in their outer shell. During the reaction, each aluminum atom loses one electron to achieve the stable octet configuration of the noble gas neon. Therefore, the number of electrons donated by one aluminum atom in this reaction is one.

The ionic equation for the reaction is:

Al3+S2- → Al3+ + S2-

Here, aluminum loses one electron to become Al3+ while sulfur gains one electron to become S2-. This single electron transfer per aluminum atom is consistent with the molecular equation given above.

I hope this helps explain the stoichiometry of electrons transferred in the reaction of aluminum sulfide! Let me know if you have any other questions.