
Определите массу соли полученной при взаимодействии 10 грамм кремния с 24% примесей с избытком
гидроксида натрия. Каков объем полученного газа

Ответы на вопрос

14)молярная масса Fe2(SO4)3=56*2+32*3+16*12=400г\моль
20)KOH+HNO3=KNO3+H2O Реакция не знаю но наверно щелочная



Calculation of the Mass of Salt Produced
To determine the mass of salt produced when 10 grams of silicon reacts with 24% impurities in excess sodium hydroxide, we need to consider the balanced chemical equation for the reaction. Unfortunately, I couldn't find a specific source that provides the balanced equation for this reaction. However, I can provide you with a general approach to solve this type of problem.
1. Write the balanced chemical equation for the reaction between silicon and sodium hydroxide, considering the impurities: - Let's assume the balanced equation is: 2Si + 2NaOH + x impurities → 2Na + x impurities + SiO2 + H2O - In this equation, x represents the number of impurities present in the reaction.
2. Determine the molar mass of silicon (Si) and sodium hydroxide (NaOH): - The molar mass of Si is approximately 28.09 g/mol. - The molar mass of NaOH is approximately 40.00 g/mol.
3. Calculate the number of moles of silicon (Si) used: - We are given that the mass of silicon used is 10 grams. - To calculate the number of moles, divide the mass by the molar mass: - Moles of Si = Mass of Si / Molar mass of Si - Moles of Si = 10 g / 28.09 g/mol
4. Determine the limiting reactant: - To determine the limiting reactant, we need to compare the moles of silicon with the moles of sodium hydroxide. - Since we don't have the exact balanced equation, we cannot directly compare the moles. However, we can assume that the reaction goes to completion and all the silicon reacts.
5. Calculate the mass of salt produced: - Since we assumed that all the silicon reacts, the moles of silicon used will be equal to the moles of salt produced. - To calculate the mass of salt produced, multiply the moles of salt by the molar mass of salt: - Mass of salt = Moles of salt * Molar mass of salt
Unfortunately, without the exact balanced equation and the molar mass of the salt produced, I cannot provide you with the specific mass of salt produced in this reaction.


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