Question

Определить обьем при н.у и число молекул 6,4 г оксида серы (IV)

Answer 1

Дано:
$m(SO_2)=6,4$г
_____________________
Найти:
$V(SO_2)-?\\N(SO_2)-?$

Решение:
1) Находим количество вещества $SO_4$:
$n(SO_2)=\frac{m}{M}={6,4}{64}=0,1$моль

2) Через кол-во вещества можно найти объём:
$V(SO_2)=Va*n(SO_4)=22,4*0,1=2,24$л

3) Таким же образом, через кол-во вещества можно найти число молекул:
$N(SO_2)=Na*n(SO_2)=6*10^2^3*0.1=0,6*10^2^3$

Ответ: $V(SO_2)=2,24$л; $n(SO_2)=0,6*10^2^3$

Answer 2

Calculating the Volume and Number of Molecules of Sulfur Dioxide (SO2) at Standard Conditions

To calculate the volume and number of molecules of 6.4g of sulfur dioxide (SO2) at standard conditions, we can use the ideal gas law and molar volume at standard conditions.

1. Calculate the Volume at Standard Conditions: - The molar mass of sulfur dioxide (SO2) is approximately 64.06 g/mol. - Using the molar mass, we can calculate the number of moles of SO2 in 6.4g. - Then, we can use the molar volume at standard conditions to calculate the volume occupied by these moles of SO2.

Calculation: - Number of moles of SO2 = Mass of SO2 / Molar mass of SO2 - Volume of SO2 at standard conditions = Number of moles of SO2 * Molar volume at standard conditions

Result: - The volume of 6.4g of sulfur dioxide at standard conditions is approximately 0.167 L.

2. Calculate the Number of Molecules: - Once we have the volume of SO2 at standard conditions, we can use Avogadro's number to calculate the number of molecules.

Calculation: - Number of molecules = Number of moles of SO2 * Avogadro's number

Result: - The number of molecules in 6.4g of sulfur dioxide at standard conditions is approximately 1.5 x 10^22 molecules.

In summary, the volume of 6.4g of sulfur dioxide at standard conditions is approximately 0.167 L, and it contains approximately 1.5 x 10^22 molecules.