Question

Какой объём углекислого газа выделится при взаимодействии 100г карбоната натрия с соляной кислотой?

Answer 1

М(Na2CO3)=106
100/106=0,943
0,943x22,4=21

Answer 2

Фиг знает куяным**
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Answer 3

Carbon Dioxide Production from Sodium Carbonate and Hydrochloric Acid

When 100g of sodium carbonate reacts with hydrochloric acid, the amount of carbon dioxide released can be calculated using stoichiometry. The balanced chemical equation for the reaction is:

Na2CO3 + 2HCl → 2NaCl + CO2 + H2O

According to the stoichiometry of the balanced chemical equation, 1 mole of sodium carbonate reacts with 2 moles of hydrochloric acid to produce 1 mole of carbon dioxide.

To calculate the amount of carbon dioxide produced, we can use the molar mass of sodium carbonate and the stoichiometry of the reaction.

The molar mass of sodium carbonate (Na2CO3) is approximately 105.99 g/mol.

Using this information, we can calculate the amount of carbon dioxide produced.

The molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol.

Using the molar mass of sodium carbonate and the stoichiometry of the reaction, we can calculate the amount of carbon dioxide produced when 100g of sodium carbonate reacts with hydrochloric acid.

Calculation: 1. Calculate the moles of sodium carbonate: - Moles of Na2CO3 = Mass of Na2CO3 / Molar mass of Na2CO3 - Moles of Na2CO3 = 100g / 105.99 g/mol

2. Use the stoichiometry of the reaction to find the moles of CO2 produced: - Moles of CO2 = Moles of Na2CO3

3. Calculate the mass of CO2 produced: - Mass of CO2 = Moles of CO2 * Molar mass of CO2

Result: The amount of carbon dioxide produced when 100g of sodium carbonate reacts with hydrochloric acid is approximately 44.01g.

This calculation is based on the stoichiometry of the balanced chemical equation and the molar masses of the substances involved.