Question

Цинк прореагировал с 300 г 10%-ного раствора соляной кислоты.Какое количество водорода образовалось?

Answer 1

Zn+2HCl=H2+ZnCl2

m HCl=300*0.1=30 г

n HCl=30/36.3=0.82 моль

n H2=0.82/2=0.41 моль

 

 

 

 

 

 

 

 

 

 

Answer 2

Reaction of Zinc with Hydrochloric Acid

When zinc reacts with hydrochloric acid, it produces zinc chloride and hydrogen gas. The balanced chemical equation for this reaction is:

Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)

To find out the amount of hydrogen gas produced when 300 g of 10% hydrochloric acid reacts with zinc, we need to calculate the amount of hydrochloric acid in moles and then use the stoichiometry of the balanced chemical equation to determine the amount of hydrogen gas produced.

Calculating the Amount of Hydrochloric Acid

First, we need to calculate the amount of hydrochloric acid in moles. The concentration of the 10% hydrochloric acid solution is 10 g/100 mL.

Given: - Mass of 10% hydrochloric acid = 300 g - Concentration of 10% hydrochloric acid = 10 g/100 mL

We can use the concentration and mass to calculate the volume of the hydrochloric acid solution and then convert it to moles using the molar mass of hydrochloric acid.

Calculating the Amount of Hydrogen Gas Produced

Once we have the amount of hydrochloric acid in moles, we can use the stoichiometry of the balanced chemical equation to determine the amount of hydrogen gas produced.

From the balanced chemical equation: - 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

Therefore, the amount of hydrogen gas produced can be calculated based on the moles of hydrochloric acid used in the reaction.

Conclusion

By following these steps, we can calculate the amount of hydrogen gas produced when 300 g of 10% hydrochloric acid reacts with zinc.