Question

Сколько кг угля пойдёт на восстановление железа из 156 кг оксида железа (II), содержащего 8% примесей?

Answer 1

2FeO+C=2Fe+CO2

n(FeO)=n(Fe)=320*0,9/72=4кмоль

m(Fe)=56кг/кмоль*4кмоль=224кг это ответ.

Answer 2

Calculating the Amount of Coal Needed to Reduce Iron Oxide

To calculate the amount of coal needed to reduce 156 kg of iron oxide (II) containing 8% impurities, we can use the following chemical equation:

Fe2O3 + 3C → 2Fe + 3CO

According to the stoichiometry of the reaction, 1 mole of iron oxide (Fe2O3) reacts with 3 moles of carbon (C) to produce 2 moles of iron (Fe) and 3 moles of carbon monoxide (CO).

Calculation Steps

1. Calculate the molar mass of Fe2O3 and C. 2. Use the molar ratio from the balanced chemical equation to find the moles of Fe2O3 and C. 3. Convert moles of C to grams and then to kilograms.

Molar Mass Calculation

The molar mass of Fe2O3 can be calculated as follows: - Molar mass of Fe = 55.85 g/mol - Molar mass of O = 16.00 g/mol - Molar mass of Fe2O3 = (2 * 55.85) + (3 * 16.00) = 159.70 g/mol

The molar mass of C is 12.01 g/mol.

Moles of Fe2O3 and C

Using the molar mass and the given mass of iron oxide (II), we can calculate the moles of Fe2O3: - Moles of Fe2O3 = Mass of Fe2O3 / Molar mass of Fe2O3 - Moles of Fe2O3 = 156 kg * 1000 g/kg / 159.70 g/mol

The moles of C required can be calculated using the stoichiometry of the reaction.

Conversion to Kilograms of Coal

Once we have the moles of C, we can convert it to grams and then to kilograms to find the amount of coal needed for the reduction.

Let's calculate the moles of Fe2O3 and C, and then convert the moles of C to kilograms of coal.

Answer

The amount of coal needed to reduce 156 kg of iron oxide (II) containing 8% impurities can be calculated using the steps above.