Question

Составьте ионное ур-е реакций. 1. Cu(No3)+Na2SO4→CuSI4+NaNO3 2. AgNO3+NaCl→AgCl+NaNO3 3. NaOH+H3PO4→Na3PO4+H2O

Answer 1

1. Cu(NO3)+Na2SO4 - реакция не идет.

2. AgNO3+NaCl=AgCl+NaNO3.
Ag+ + NO3- + Na+ + Cl- = AgCl (осадок) + Na+ + NO3-.

3. 3NaOH+H3PO4=Na3PO4+3H2O.
3Na+ + 3OH- + H3+ + PO4 3-= Na3+ + PO4 3- + 3H2O.

Answer 2

Ionic Equations for the Given Reactions:

1. Cu(NO3)2 + 2Na2SO4 → CuSO4 + 2NaNO3 2. AgNO3 + NaCl → AgCl + NaNO3 3. 3NaOH + H3PO4 → Na3PO4 + 3H2O

Let's break down each reaction and write the balanced ionic equations.

1. Cu(NO3)2 + 2Na2SO4 → CuSO4 + 2NaNO3

To write the ionic equation, we need to break down the compounds into their respective ions:

Cu(NO3)2 → Cu^2+ + 2NO3^- Na2SO4 → 2Na^+ + SO4^2-

Now, let's write the balanced ionic equation by swapping the positive and negative ions:

Cu^2+ + SO4^2- + 2Na^+ + 2NO3^- → CuSO4 + 2Na^+ + 2NO3^-

Simplifying the equation by canceling out the common ions on both sides:

Cu^2+ + SO4^2- → CuSO4

Therefore, the ionic equation for the reaction is: Cu^2+ + SO4^2- → CuSO4

2. AgNO3 + NaCl → AgCl + NaNO3

Breaking down the compounds into ions:

AgNO3 → Ag^+ + NO3^- NaCl → Na^+ + Cl^-

Writing the balanced ionic equation:

Ag^+ + NO3^- + Na^+ + Cl^- → AgCl + Na^+ + NO3^-

Simplifying the equation:

Ag^+ + Cl^- → AgCl

The ionic equation for the reaction is: Ag^+ + Cl^- → AgCl

3. 3NaOH + H3PO4 → Na3PO4 + 3H2O

Breaking down the compounds into ions:

3NaOH → 3Na^+ + 3OH^- H3PO4 → H^+ + H2PO4^-

Writing the balanced ionic equation:

3Na^+ + 3OH^- + H^+ + H2PO4^- → Na3PO4 + 3H2O

Simplifying the equation:

3Na^+ + H^+ + H2PO4^- → Na3PO4 + 3H2O

The ionic equation for the reaction is: 3Na^+ + H^+ + H2PO4^- → Na3PO4 + 3H2O

Please note that these equations represent the ionic species involved in the reactions and do not account for the physical state or stoichiometry of the compounds.