Question

Водяной пар пропускают над раскаленным углем, формируется водяной газ. вычислите объем водяного газа полученный из 180 г воды

Answer 1

H2O+C=CO+H2
n(h20)=n(CO)=180/18= 10моль
v(co)=10*22.4 =224 дм3

Answer 2

Calculating the Volume of Water Gas Produced

When passing steam over hot carbon, water gas is formed according to the following equation:

C + H2O → CO + H2

To calculate the volume of water gas produced from 180 g of water, we can use the stoichiometry of the reaction.

The molar mass of water (H2O) is 18 g/mol, and the molar mass of water gas (H2) is 2 g/mol.

First, we need to convert the mass of water (180 g) to moles, and then use the stoichiometric coefficients from the balanced chemical equation to find the moles of water gas produced. Finally, we can convert the moles of water gas to volume at standard temperature and pressure (STP).

Calculation Steps:

1. Convert mass of water to moles: - Moles of water = Mass of water / Molar mass of water - Moles of water = 180 g / 18 g/mol - Moles of water = 10 moles

2. Use stoichiometry to find moles of water gas produced: - From the balanced chemical equation, 1 mole of water produces 1 mole of water gas. - Moles of water gas produced = Moles of water

3. Convert moles of water gas to volume at STP: - 1 mole of any gas at STP occupies 22.4 liters. - Volume of water gas produced = Moles of water gas * 22.4 L/mol

Calculation:

- Moles of water = 180 g / 18 g/mol = 10 moles - Moles of water gas produced = 10 moles - Volume of water gas produced = 10 moles * 22.4 L/mol = 224 liters

Therefore, the volume of water gas produced from 180 g of water is 224 liters.