Question

Вычислите массу кремниевой кислоты которую можно получить при взаимодействии силиката натрия и раствора соляной кислоты массой 73г с массовой долей ее 25%

Answer 1

Na2SiO3+2HCl=2NaCl+H2SiO3
                2 моль------------1 моль
m(HCl)=73*0.25=18.25 г
n(HCl)=18.25:36.5=0.5 моль
n(H2SiO3)=0.5:2=0.25 моль
m(H2SiO3)=0.25*78=19.5 г
M(H2SiO3)=78

Answer 2

Calculating the Mass of Siliconic Acid

To calculate the mass of siliconic acid that can be obtained from the reaction between sodium silicate and a solution of hydrochloric acid with a mass of 73g and a mass fraction of 25%, we can use the following steps:

1. Determine the Chemical Equation for the Reaction: - The reaction between sodium silicate and hydrochloric acid can be represented by the following chemical equation: ``` Na2SiO3 + 2HCl → H2SiO3 + 2NaCl ```

2. Calculate the Molar Mass of Sodium Silicate (Na2SiO3): - The molar mass of sodium silicate (Na2SiO3) can be calculated by adding the atomic masses of its constituent elements. - The molar mass of sodium (Na) is 22.99 g/mol, silicon (Si) is 28.0855 g/mol, and oxygen (O) is 16.00 g/mol.

3. Determine the Limiting Reagent: - The limiting reagent is the reactant that is completely consumed in a chemical reaction and limits the amount of product that can be formed. - To find the limiting reagent, we need to compare the amount of each reactant to the stoichiometry of the balanced chemical equation.

4. Calculate the Mass of Siliconic Acid Produced: - Once the limiting reagent is identified, the mass of siliconic acid produced can be calculated based on the stoichiometry of the reaction.

Let's proceed with the calculations based on the provided information and the steps outlined above.

Calculation Steps

1. Molar Mass of Sodium Silicate (Na2SiO3): - The molar mass of sodium silicate (Na2SiO3) can be calculated as follows: - Molar mass of Na2SiO3 = 2 * molar mass of Na + molar mass of Si + 3 * molar mass of O - Molar mass of Na2SiO3 = 2 * 22.99 g/mol + 28.0855 g/mol + 3 * 16.00 g/mol - Molar mass of Na2SiO3 = 46.0 g/mol + 28.0855 g/mol + 48.00 g/mol - Molar mass of Na2SiO3 = 122.0855 g/mol

2. Determine the Limiting Reagent: - To determine the limiting reagent, we need to compare the amount of sodium silicate and hydrochloric acid to the stoichiometry of the balanced chemical equation.

3. Calculate the Mass of Siliconic Acid Produced: - Once the limiting reagent is identified, the mass of siliconic acid produced can be calculated based on the stoichiometry of the reaction.

Based on the provided information, the specific details required to complete the calculation are not available. If you have the necessary information, such as the amount of sodium silicate and the concentration of the hydrochloric acid solution, please provide those details so that I can proceed with the calculation.