Question

Определите, какой объём (н.у.) хлороводорода образуется при горении 50 М3 водорода в хлоре.

Answer 1

H2 + Cl2  = 2 HCl

по уравнению видно, что HCl в 2 раза  больше по молям, чем водорода, для газов соотношение молей = соотношению объемов

50 * 2 = 100 м3 HCl

Answer 2

Calculating the Volume of Hydrochloric Acid Produced

To determine the volume of hydrochloric acid (HCl) produced when 50 m3 of hydrogen (H2) is burned in chlorine (Cl2), we can use the balanced chemical equation for the reaction between hydrogen and chlorine to form hydrochloric acid:

H2 + Cl2 → 2HCl

According to the balanced chemical equation, 1 mole of hydrogen reacts with 1 mole of chlorine to produce 2 moles of hydrochloric acid.

Calculation Steps

1. Calculate the moles of hydrogen present in 50 m3. 2. Use the mole ratio from the balanced chemical equation to find the moles of hydrochloric acid produced. 3. Convert the moles of hydrochloric acid to volume using the ideal gas law.

Step 1: Calculate the Moles of Hydrogen

The molar volume of any gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, the moles of hydrogen can be calculated as follows:

Moles of H2 = Volume of H2 / Molar Volume at STP

Moles of H2 = 50 m3 / 22.4 L/mole

Step 2: Use the Mole Ratio

According to the balanced chemical equation, 1 mole of hydrogen reacts with 1 mole of chlorine to produce 2 moles of hydrochloric acid. Therefore, the moles of hydrochloric acid produced will be twice the moles of hydrogen.

Moles of HCl = 2 * Moles of H2

Step 3: Convert Moles to Volume

Finally, we can use the ideal gas law to convert the moles of hydrochloric acid to volume. At STP, 1 mole of any gas occupies 22.4 L.

Volume of HCl = Moles of HCl * Molar Volume at STP

Volume of HCl = Moles of HCl * 22.4 L/mole

By following these steps, the volume of hydrochloric acid produced when 50 m3 of hydrogen is burned in chlorine can be calculated.