Question

Какую массу имеют 3,01 * 10^23 молекул этана?

Answer 1

M = n*M
n = N/N(a)
M(C2H6) = 12*2+6 = 30 г/моль
N(a) = 6.02*10^23
n(C2H6) = 3.01*10^23/6.02*10^23 = 0.5 моль
m(C2H6) = 0.5*30 = 15 г

Answer 2

Calculating the Mass of 3.01 * 10^23 Molecules of Ethane

To calculate the mass of 3.01 * 10^23 molecules of ethane, we can use the molar mass of ethane and Avogadro's number.

Molar Mass of Ethane: The molar mass of ethane (C2H6) can be calculated by adding the atomic masses of its constituent atoms.

The atomic masses are: - Carbon (C): 12.01 g/mol - Hydrogen (H): 1.008 g/mol

The molar mass of ethane (C2H6) = (2 * 12.01 g/mol) + (6 * 1.008 g/mol) = 30.07 g/mol.

Calculating the Mass: Now, we can calculate the mass of 3.01 * 10^23 molecules of ethane using the molar mass and Avogadro's number.

The number of moles (n) can be calculated using the formula: n = N / NA where N is the number of molecules and NA is Avogadro's number (6.02 * 10^23 mol^-1).

Substituting the values: n = 3.01 * 10^23 / 6.02 * 10^23 n ≈ 0.5 moles

The mass (m) can be calculated using the formula: m = n * M where M is the molar mass.

Substituting the values: m ≈ 0.5 moles * 30.07 g/mol m ≈ 15.035 g

Therefore, the mass of 3.01 * 10^23 molecules of ethane is approximately 15.035 grams.