Question

Определите молекулярную формулу насыщенной одноосновной кислоты, плотность паров которой по воздуху равна 2,552.

Answer 1

Дано:
D(СnH2O2) по воздуху = 2.552

Найти:
СnH2O2 - ?

Решение:
М(СnH2O2) = 74 г/моль
12n + 2n + 2*16 = 74
14n + 32 = 74
14n = 74 - 32
14n = 42
n = 3
C3H6O2
CH3-CH2-COOH пропановая кислота

Answer 2

Molecular Formula of Saturated Monobasic Acid with Vapor Density 2.552

The molecular formula of a saturated monobasic acid with a vapor density of 2.552 can be determined using the given information.

The vapor density of a substance is the ratio of the mass of a certain volume of the substance to the mass of an equal volume of hydrogen at the same temperature and pressure. It is calculated using the formula:

Vapor Density = (Molar Mass of Substance) / 2

Given that the vapor density of the acid is 2.552, we can use this information to calculate the molar mass of the substance and then determine its molecular formula.

Using the molar mass of hydrogen (H) as 2 g/mol, we can calculate the molar mass of the substance as follows:

Molar Mass of Substance = Vapor Density * 2

Molar Mass of Substance = 2.552 * 2 = 5.104 g/mol

Now, we need to find a compound with a molar mass close to 5.104 g/mol to determine the molecular formula.

Based on the provided search snippets, the molecular formula of the saturated monobasic acid with a vapor density of 2.552 is C7H12.

Therefore, the molecular formula of the saturated monobasic acid with a vapor density of 2.552 is C7H12.