Question

Помогите ,пожалуйста ,ооочень нужно. Нитратная кислота массой 100 грамм, с массовой долей 20% взаимодействует с медью .Какова масса образовавшийся соли ,если выход продукта реакции 89%?

Answer 1

HNO3+Cu=Cu(NO3)2+2NO2+2H2O
m(HNO3)=20г
m(Cu(NO3)2)=((20*187.5)\63)*0.89=53г

Answer 2

Calculation of the Mass of the Salt Formed

To calculate the mass of the salt formed when 100 grams of nitric acid with a mass fraction of 20% reacts with copper, we need to consider the reaction and the stoichiometry involved.

The balanced chemical equation for the reaction between nitric acid (HNO3) and copper (Cu) can be written as follows:

2HNO3 + 3Cu → 3Cu(NO3)2 + 2H2O

From the balanced equation, we can see that 2 moles of nitric acid react with 3 moles of copper to produce 3 moles of copper nitrate and 2 moles of water.

To determine the mass of the salt formed, we need to calculate the number of moles of nitric acid and then use the stoichiometry of the reaction to find the number of moles of copper nitrate formed. Finally, we can convert the moles of copper nitrate to grams using its molar mass.

Let's calculate the mass of the salt formed step by step:

1. Calculate the number of moles of nitric acid: - Mass of nitric acid = 100 grams - Mass fraction of nitric acid = 20% - Mass of nitric acid in the solution = 100 grams * (20/100) = 20 grams - Molar mass of nitric acid (HNO3) = 63.01 g/mol - Number of moles of nitric acid = Mass of nitric acid / Molar mass of nitric acid = 20 grams / 63.01 g/mol = 0.317 moles

2. Use the stoichiometry of the reaction to find the number of moles of copper nitrate formed: - According to the balanced equation, 2 moles of nitric acid react with 3 moles of copper to produce 3 moles of copper nitrate. - Therefore, the number of moles of copper nitrate formed = (0.317 moles * 3 moles) / 2 moles = 0.476 moles

3. Convert the moles of copper nitrate to grams using its molar mass: - Molar mass of copper nitrate (Cu(NO3)2) = 187.56 g/mol - Mass of copper nitrate formed = Number of moles of copper nitrate * Molar mass of copper nitrate = 0.476 moles * 187.56 g/mol = 89.35 grams

Therefore, the mass of the salt formed when 100 grams of nitric acid with a mass fraction of 20% reacts with copper, with a reaction yield of 89%, is approximately 89.35 grams.

Please note that the above calculation assumes ideal conditions and a complete reaction. In practice, the actual yield may vary due to factors such as side reactions and incomplete conversion.