Question

Пожалуйста помогите срочно((( В сосуде объемом 2 л смешали газ А количеством вещества 4,5 моль и газ В количеством вещества 3 моль. Газы А и В реагируют в соответствии с уравнением А + В = С. Через 20 с в системе образовался газ С количеством вещества 2 моль. Определите среднюю скорость реакции. Какие количества непрореаги-ровавших газов А и В остались в системе?

Answer 1

из интернета взято..... надеюсь правильно

Answer 2

Reaction Stoichiometry and Average Reaction Rate

To determine the average reaction rate and the quantities of unreacted gases A and B remaining in the system, we can use the given information about the reaction and the quantities of substances involved.

The balanced chemical equation for the reaction is: A + B → C

Given: - Volume of the vessel: 2 L - Quantity of substance of gas A: 4.5 moles - Quantity of substance of gas B: 3 moles - Quantity of substance of gas C formed after 20 seconds: 2 moles

Average Reaction Rate Calculation

The average reaction rate can be calculated using the formula: Average Reaction Rate = (Change in concentration of C) / (Time interval)

Since the reaction stoichiometry is not provided, we can assume that the stoichiometry of the reaction is 1:1 for A and B reacting to form C. Therefore, the change in concentration of C is equal to the quantity of substance of C formed, which is 2 moles.

Given that the time interval is 20 seconds, we can calculate the average reaction rate: Average Reaction Rate = 2 moles / 20 seconds = 0.1 moles/second

Quantities of Unreacted Gases A and B

To determine the quantities of unreacted gases A and B remaining in the system, we can use the stoichiometry of the reaction.

Since the stoichiometry is 1:1 for A and B reacting to form C, the limiting reactant will be the one that is completely consumed. We can use the stoichiometry to determine the quantities of unreacted gases A and B.

Given that the reaction produced 2 moles of C, and assuming the stoichiometry is 1:1, the limiting reactant will be the one that produces the least amount of C. Therefore, the limiting reactant will be the reactant that was initially present in the smallest quantity.

Let's calculate the quantities of unreacted gases A and B:

- Unreacted quantity of A = Initial quantity of A - moles of A reacted - Unreacted quantity of A = 4.5 moles - 2 moles = 2.5 moles

- Unreacted quantity of B = Initial quantity of B - moles of B reacted - Unreacted quantity of B = 3 moles - 2 moles = 1 mole

Therefore, the quantities of unreacted gases A and B remaining in the system are: - Unreacted quantity of A: 2.5 moles - Unreacted quantity of B: 1 mole

So, the average reaction rate is 0.1 moles/second, and the quantities of unreacted gases A and B remaining in the system are 2.5 moles and 1 mole respectively.