Question

Закончите уравнения реакций, расставив коэффициенты методом электронно-ионного (или электронного) баланса: As2O3 + I2 + KOH = K3AsO4 + KI + H2O Нужна краткая,полная и молекулярная ионная схема. И что явялется окислителем, а что восстановителем. Заранее спасибо))

Answer 1

Ответ см. в прикрепленном ниже файле

Answer 2

Equation Balancing:

To balance the given equation using the method of electron-ion balance, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

As2O3 + I2 + KOH → K3AsO4 + KI + H2O

Ionic Equation:

The ionic equation represents the reaction in terms of individual ions. Here's the ionic equation for the given reaction:

2As3+ + 3O2- + 2I2 + 2K+ + 2OH- → 2K+ + AsO4^3- + 2I- + H2O

Molecular Equation:

The molecular equation represents the reaction in terms of complete compounds. Here's the molecular equation for the given reaction:

As2O3 + 3I2 + 6KOH → 2K3AsO4 + 6KI + 3H2O

Oxidizing and Reducing Agents:

In the given reaction, the oxidizing agent is the species that gets reduced, while the reducing agent is the species that gets oxidized.

In this case, I2 is the oxidizing agent because it gains electrons and gets reduced to 2I-.

On the other hand, As2O3 is the reducing agent because it loses electrons and gets oxidized to AsO4^3-.

I hope this helps! Let me know if you have any further questions.