Question

Расставьте коэффициенты методом электронного баланса, укажите окислитель и восстановитель:а) HNO3 + S = H2SO4 + NO ↑б) V2O5 + H2C2O1 = VO2 + CO2 + H2O

Answer 1

A)2HNO3+S=H2SO4+2NO
S-восстановитель
N-окислитель
б)2V2O5+H2C2O=4VO2+CO2+H20

Answer 2

А) 2HNO3 + S = H2SO4+ 2NO
b) 2V2O5+ H2CO= 4VO2+ CO2+H2O

Answer 3

Balancing the Equation: HNO3 + S = H2SO4 + NO

To balance the equation using the method of electronic balancing, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

1. Start by balancing the atoms that appear in only one compound on each side of the equation. In this case, we have: - Nitrogen (N): There is 1 nitrogen atom on the left side (HNO3) and 1 nitrogen atom on the right side (NO). - Sulfur (S): There is 1 sulfur atom on the left side (S) and 1 sulfur atom on the right side (H2SO4).

2. Next, balance the atoms that appear in multiple compounds on each side of the equation. In this case, we have: - Hydrogen (H): There are 3 hydrogen atoms on the left side (HNO3) and 4 hydrogen atoms on the right side (H2SO4). To balance the hydrogen atoms, we can add 1 more hydrogen atom to the left side, resulting in HNO3 + H2O. - Oxygen (O): There are 3 oxygen atoms on the left side (HNO3) and 6 oxygen atoms on the right side (H2SO4). To balance the oxygen atoms, we can add 3 more oxygen atoms to the left side, resulting in HNO3 + 3H2O.

The balanced equation is: HNO3 + 3H2O + S = H2SO4 + NO.

In this equation, HNO3 is the oxidizing agent (or oxidant) because it is being reduced, and S is the reducing agent (or reductant) because it is being oxidized.

Balancing the Equation: V2O5 + H2C2O4 = VO2 + CO2 + H2O

To balance the equation using the method of electronic balancing, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

1. Start by balancing the atoms that appear in only one compound on each side of the equation. In this case, we have: - Vanadium (V): There are 2 vanadium atoms on the left side (V2O5) and 1 vanadium atom on the right side (VO2). - Carbon (C): There are 2 carbon atoms on the left side (H2C2O4) and 1 carbon atom on the right side (CO2). - Hydrogen (H): There are 4 hydrogen atoms on the left side (H2C2O4) and 2 hydrogen atoms on the right side (H2O).

2. Next, balance the atoms that appear in multiple compounds on each side of the equation. In this case, we have: - Oxygen (O): There are 5 oxygen atoms on the left side (V2O5) and 4 oxygen atoms on the right side (VO2 + CO2 + H2O). To balance the oxygen atoms, we can add 1 more oxygen atom to the right side, resulting in V2O5 + H2C2O4 = VO2 + CO2 + H2O + O.

The balanced equation is: V2O5 + H2C2O4 = VO2 + CO2 + H2O + O.

In this equation, V2O5 is the oxidizing agent (or oxidant) because it is being reduced, and H2C2O4 is the reducing agent (or reductant) because it is being oxidized.

Please note that the coefficients in the balanced equations may not be the smallest whole numbers. However, they represent the correct ratio of molecules or moles involved in the reaction.