Question

Составить электронный баланс, указать окислитель и восстановитель, расставить коэффициенты: а)HClO+Br₂+H₂O=HBrO₃+HCl б) PbO₂+Na₂CrO₃+NaOH= Na₂PbO₂+H₂Oпожалуйста

Answer 1

A) HClO+Br₂+H₂O=HBrO₃+HCl 
Cl окислитель, Br восстановитель
б) PbO₂+Na₂CrO₃+NaOH= Na₂PbO₂+H₂O 
2 только эл. баланс, дальше сам sorry(

Answer 2

Balancing the Equation: HClO + Br₂ + H₂O = HBrO₃ + HCl

To balance the equation: HClO + Br₂ + H₂O = HBrO₃ + HCl, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

1. Start by balancing the atoms that appear in only one compound on each side of the equation. In this case, we have: - Chlorine (Cl): There is one Cl atom on the left side (in HClO) and one Cl atom on the right side (in HCl). It is already balanced. - Bromine (Br): There are two Br atoms on the left side (in Br₂) and one Br atom on the right side (in HBrO₃). We need to balance the Br atoms.

2. To balance the Br atoms, we can place a coefficient of 2 in front of HBrO₃: HClO + Br₂ + H₂O = 2HBrO₃ + HCl

3. Now, let's balance the hydrogen (H) and oxygen (O) atoms: - Hydrogen (H): There are two H atoms on the left side (in HClO) and two H atoms on the right side (in HBrO₃ and HCl). It is already balanced. - Oxygen (O): There are three O atoms on the left side (in HClO and H₂O) and six O atoms on the right side (in HBrO₃ and HCl). We need to balance the O atoms.

4. To balance the O atoms, we can place a coefficient of 3 in front of HClO and a coefficient of 3 in front of H₂O: 3HClO + Br₂ + 3H₂O = 2HBrO₃ + HCl

5. Finally, let's check if all the atoms are balanced: - Chlorine (Cl): 1 Cl atom on both sides. - Bromine (Br): 2 Br atoms on both sides. - Hydrogen (H): 6 H atoms on both sides. - Oxygen (O): 6 O atoms on both sides.

Therefore, the balanced equation is: 3HClO + Br₂ + 3H₂O = 2HBrO₃ + HCl.

In this equation, HClO is the oxidizing agent because it is reduced from a higher oxidation state (+1) to a lower oxidation state (-1) in HCl. Br₂ is the reducing agent because it is oxidized from a zero oxidation state to a +5 oxidation state in HBrO₃.

Balancing the Equation: PbO₂ + Na₂CrO₃ + NaOH = Na₂PbO₂ + H₂O

To balance the equation: PbO₂ + Na₂CrO₃ + NaOH = Na₂PbO₂ + H₂O, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

1. Start by balancing the atoms that appear in only one compound on each side of the equation. In this case, we have: - Lead (Pb): There is one Pb atom on the left side (in PbO₂) and one Pb atom on the right side (in Na₂PbO₂). It is already balanced. - Oxygen (O): There two O atoms on the left side (in PbO₂) and two O atoms on the right side (in Na₂PbO₂). It is already balanced.

2. Now, let's balance the sodium (Na) atoms: - Sodium (Na): There are two Na atoms on the left side (in Na₂CrO₃) and two Na atoms on the right side (in Na₂PbO₂). It is already balanced.

3. Finally, let's balance the hydrogen (H) atoms: - Hydrogen (H): There is one H atom on the left side (in NaOH) and two H atoms on the right side (in H₂O). We need to balance the H atoms.

4. To balance the H atoms, we can place a coefficient of 2 in front of NaOH: PbO₂ + Na₂CrO₃ + 2NaOH = Na₂PbO₂ + H₂O

5. Now, let's check if all the atoms are balanced: - Lead (Pb): 1 Pb atom on both sides. - Oxygen (O): 2 O atoms on both sides. - Sodium (Na): 2 Na atoms on both sides. - Hydrogen (H): 2 H atoms on both sides.

Therefore, the balanced equation is: PbO₂ + Na₂CrO₃ + 2NaOH = Na₂PbO₂ + H₂O.

In this equation, Na₂CrO₃ is the oxidizing agent because it is reduced from a +6 oxidation state to a +4 oxidation state in Na₂PbO₂. PbO₂ is the reducing agent because it is oxidized from a +4 oxidation state to a +2 oxidation state in Na₂PbO₂.