Question

Рассчитать массу кальций оксида, необходимого для реакции с 12,6 г нитратной кислоты.

Answer 1

         Х г                        12,6 г
        СaO          +         2HNO3      ->     Ca(NO3)2     +     H2O
  n=1 моль                    n=2 моль
М = 56 г/моль              М = 63 г/моль
m=56 г                          m=126 г

Х г СаО     -     12,6 г HNO3
56 г СаО    -     126 г HNO3
m(CaO) = 56 * 12,6 / 126 = 5,6 г

Answer 2

Calculating the Mass of Calcium Oxide

To calculate the mass of calcium oxide required for the reaction with 12.6 g of nitric acid, we can use the balanced chemical equation for the reaction between calcium oxide and nitric acid. The balanced chemical equation for the reaction is:

CaO + 2HNO3 → Ca(NO3)2 + H2O

From the balanced chemical equation, we can see that 1 mole of calcium oxide reacts with 2 moles of nitric acid.

Using the molar mass of calcium oxide (CaO) and nitric acid (HNO3), we can calculate the mass of calcium oxide required.

The molar mass of calcium oxide (CaO) is approximately 56.08 g/mol. The molar mass of nitric acid (HNO3) is approximately 63.015 g/mol.

Calculation

Given: Mass of nitric acid (HNO3) = 12.6 g

To calculate the mass of calcium oxide required, we can use the following steps:

1. Calculate the number of moles of nitric acid using its molar mass: Moles of HNO3 = Mass of HNO3 / Molar mass of HNO3 Moles of HNO3 = 12.6 g / 63.015 g/mol Moles of HNO3 ≈ 0.2 moles

2. Use the mole ratio from the balanced chemical equation to find the moles of calcium oxide required: Moles of CaO = Moles of HNO3 / 2 Moles of CaO ≈ 0.2 moles / 2 Moles of CaO ≈ 0.1 moles

3. Calculate the mass of calcium oxide required using its molar mass: Mass of CaO = Moles of CaO * Molar mass of CaO Mass of CaO ≈ 0.1 moles * 56.08 g/mol Mass of CaO ≈ 5.608 g

Therefore, the mass of calcium oxide required for the reaction with 12.6 g of nitric acid is approximately 5.608 grams.