Question

Определите массу получившегося вещества при взаимодействии 4 г кальция с кислородом.

Answer 1

2Ca+O2=2CaO

V(ca)=4/40=0,1 моль

V(CaO=V(Ca)=0,1 моль

m(CaO)=0,1*56=5,6моль

Answer 2

Calculating the Mass of the Resulting Substance

When calcium reacts with oxygen, it forms calcium oxide (CaO). To determine the mass of the resulting substance, we need to calculate the molar mass of calcium oxide and then use the stoichiometry of the reaction to find the mass.

The molar mass of calcium (Ca) is approximately 40.08 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. The molar mass of calcium oxide (CaO) is the sum of the molar masses of calcium and oxygen, which is 40.08 g/mol + 16.00 g/mol = 56.08 g/mol.

Now, using the stoichiometry of the reaction, we can calculate the mass of the resulting substance. The balanced chemical equation for the reaction is:

2Ca + O2 → 2CaO

This equation tells us that 2 moles of calcium react with 1 mole of oxygen to produce 2 moles of calcium oxide.

Given that the mass of calcium is 4 g, we can calculate the mass of calcium oxide produced using the molar ratio from the balanced chemical equation:

4 g Ca × (1 mol CaO / 2 mol Ca) × (56.08 g CaO / 1 mol CaO) = X g CaO

By performing the calculation, we find that the mass of the resulting substance when 4 g of calcium reacts with oxygen is approximately 56.08 g of calcium oxide.

Therefore, the mass of the resulting substance when 4 g of calcium reacts with oxygen is approximately 56.08 g of calcium oxide.