Question

Найдите массу соли которая образуется при взаимодействии 2,7 граммов аллюминия с H2SO4

Answer 1

2Al+3H2SO4=Al2(SO4)3+3H2 17.1грамм соли

Answer 2

Calculating the Mass of Salt Formed from the Reaction of Aluminum with H2SO4

To calculate the mass of salt formed when 2.7 grams of aluminum reacts with H2SO4, we can use the balanced chemical equation for the reaction and the molar masses of the substances involved.

The balanced chemical equation for the reaction of aluminum with sulfuric acid (H2SO4) is:

2 Al + 3 H2SO4 → Al2(SO4)3 + 3 H2

From the equation, we can see that 2 moles of aluminum react with 3 moles of sulfuric acid to produce 1 mole of aluminum sulfate (Al2(SO4)3).

The molar mass of aluminum is approximately 26.98 g/mol, and the molar mass of sulfuric acid (H2SO4) is approximately 98.08 g/mol.

Using this information, we can calculate the mass of aluminum sulfate formed.

The first step is to calculate the number of moles of aluminum present: Number of moles of aluminum = Given mass of aluminum / Molar mass of aluminum Number of moles of aluminum = 2.7 g / 26.98 g/mol

Now, we can use the mole ratio from the balanced chemical equation to find the number of moles of aluminum sulfate formed: Number of moles of aluminum sulfate = Number of moles of aluminum * (1 mole of Al2(SO4)3 / 2 moles of Al)

Finally, we can calculate the mass of aluminum sulfate formed: Mass of aluminum sulfate = Number of moles of aluminum sulfate * Molar mass of aluminum sulfate

Let's calculate the mass of aluminum sulfate formed.