Question

К 230 г 25%-ного раствора соли добавили 22.5 г

Answer 1

Дано:
m(р-ра)=230г+22.5г(соли)
w1=25%
найти:
w2=?
решение:
m(соли)=230×25/100=57.5г
w2=(57.5+22.5)×100%/(230+22.5)=3%
ответ:w2=3%

Answer 2

Calculation of the Resulting Solution

To calculate the resulting solution when 22.5 grams of a 25% salt solution is added to a 230 gram solution, we need to consider the amount of salt in each solution and then combine them.

The 25% salt solution contains 25 grams of salt per 100 grams of solution. Therefore, the amount of salt in the 25% solution is:

Amount of salt in the 25% solution = (25/100) * 230 grams = 57.5 grams.

When we add 22.5 grams of the 25% salt solution to the existing solution, the total amount of salt in the resulting solution will be:

Total amount of salt = Amount of salt in the 25% solution + Amount of salt added = 57.5 grams + 22.5 grams = 80 grams.

Therefore, the resulting solution will contain 80 grams of salt.

Calculation of the Concentration of the Resulting Solution

To calculate the concentration of the resulting solution, we need to determine the total volume of the resulting solution. Since we are adding 22.5 grams of the 25% salt solution to a 230 gram solution, we can assume that the volume remains constant.

The concentration of a solution is defined as the amount of solute (in this case, salt) divided by the volume of the solution. Therefore, the concentration of the resulting solution can be calculated as:

Concentration of the resulting solution = (Total amount of salt) / (Total volume of the resulting solution).

Since the volume remains constant, we can express the concentration as:

Concentration of the resulting solution = (Total amount of salt) / 230 grams.

Substituting the value of the total amount of salt (80 grams) into the equation, we get:

Concentration of the resulting solution = 80 grams / 230 grams ≈ 0.348 or 34.8%.

Therefore, the concentration of the resulting solution is approximately 34.8%.

Please note that these calculations assume that the volume of the solution remains constant when the salt solution is added.