Question

Сколько граммов серной кислоты содержится в 1 мл 0,1000 н раствора?

Answer 1

M(H₂SO₄) = Cn*V*Mэ(H₂SO₄) =  0,1*0,001л* 49 г\моль = 0,0049 г.

Answer 2

Calculating the Amount of Sulfuric Acid in a 0.1000 N Solution

To calculate the amount of sulfuric acid in a 0.1000 N solution, we can use the formula:

N = Molarity * Equivalent weight

Where: - N = Normality of the solution - Molarity = Molar concentration of the solution - Equivalent weight = Gram equivalent weight of the solute

In the case of sulfuric acid (H2SO4), the equivalent weight is 49 g/equiv.

Calculation

Given: - Molarity (N) = 0.1000 N - Volume (V) = 1 mL - Equivalent weight of sulfuric acid = 49 g/equiv

We can use the formula to calculate the amount of sulfuric acid:

Equivalent weight = (Molarity * Volume) / 1000

Substituting the given values: Equivalent weight = (0.1000 * 1) / 1000 = 0.0001 equiv

Now, to find the amount of sulfuric acid in grams: Amount of sulfuric acid = Equivalent weight * Gram equivalent weight Amount of sulfuric acid = 0.0001 equiv * 49 g/equiv = 0.0049 g

So, there are 0.0049 grams of sulfuric acid in 1 mL of 0.1000 N solution.