Question

Вычислите степень окисления и определите валентность атомов метана

Answer 1

Сн4- степень окисления водорода всегда +1 соответстенно у углерода она -4 тк атомов водорода 4 а атомов углерода 1 . валентность углерода 4 римской цифрой . водорода 1

Answer 2

Calculation of Oxidation State and Valency of Methane

To calculate the oxidation state and determine the valency of atoms in methane (CH4), we need to understand the concept of oxidation state and valency.

Oxidation state (also known as oxidation number) is a measure of the degree of oxidation of an atom in a chemical compound. It indicates the number of electrons that an atom has gained or lost when it forms a compound. Oxidation state can be positive, negative, or zero.

Valency refers to the combining capacity of an atom, which is determined by the number of electrons it can gain, lose, or share when it forms chemical bonds.

Now, let's calculate the oxidation state and determine the valency of the atoms in methane (CH4).

In methane (CH4), carbon (C) is bonded to four hydrogen (H) atoms. To calculate the oxidation state of carbon, we can assign a hypothetical oxidation state to hydrogen and use it to determine the oxidation state of carbon.

Let's assume the oxidation state of hydrogen (H) in methane is +1. Since there are four hydrogen atoms, the total oxidation state contributed by hydrogen is +4.

The sum of the oxidation states in a neutral molecule is zero. Therefore, the oxidation state of carbon (C) can be calculated as follows:

Oxidation state of carbon (C) = Total oxidation state contributed by hydrogen - Total oxidation state of hydrogen = +4 - 4 = 0

Hence, the oxidation state of carbon in methane (CH4) is 0.

Now, let's determine the valency of the atoms in methane.

The valency of an atom is equal to the absolute value of its oxidation state. Since the oxidation state of carbon in methane is 0, the valency of carbon is also 0.

Similarly, assuming the oxidation state of hydrogen is +1, the valency of hydrogen in methane is +1.

To summarize: - The oxidation state of carbon (C) in methane (CH4) is 0. - The valency of carbon (C) in methane (CH4) is 0. - The oxidation state of hydrogen (H) in methane (CH4) is +1. - The valency of hydrogen (H) in methane (CH4) is +1.

Please note that these calculations are based on the assumption that the oxidation state of hydrogen in methane is +1. The actual oxidation state of hydrogen can vary depending on the specific chemical reaction or context.

I hope this explanation helps! Let me know if you have any further questions.