Question

сколько граммов хлорида бария следует растворить в 500г воды для получения 10% раствора?

Answer 1

Всего раствора 100 %, тогда 500 г воды будет занимать - 90 %, а хлорид бария  - 10 %. Составим пропорцию: 500 г - 90 %

                                  х г    - 10 %

Получим: х = 500*10:90 = 55,556 г.

Проверим: 55,556:(500+55,556)*100%=10% - решение верно

Answer 2

500     -         90%
 x          -        10% 
x=  56 гр (m(BaCl2))

Answer 3

Calculating the Amount of Barium Chloride to Make a 10% Solution

To calculate the amount of barium chloride needed to make a 10% solution in 500g of water, we can use the formula for calculating the concentration of a solution:

Concentration = (mass of solute / total mass of solution) * 100

In this case, we want to find the mass of barium chloride needed to make a 10% solution in 500g of water.

Calculation

Using the given formula, we can calculate the mass of barium chloride needed:

10% = (mass of barium chloride / (mass of barium chloride + 500g)) * 100

Solving for the mass of barium chloride:

mass of barium chloride = (10/100) * (mass of barium chloride + 500g)

mass of barium chloride = 0.1 * (mass of barium chloride + 500g)

mass of barium chloride = 50g

So, 50 grams of barium chloride should be dissolved in 500g of water to obtain a 10% solution.