Question

Выведите молекулярную формулу углеводорода, массовая доля водорода в котором 14,3% , а плотность паров этого вещества по воз духу равна 3,86

Answer 1

Фото
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Answer 2

Molecular Formula of the Hydrocarbon

The molecular formula of the hydrocarbon with a hydrogen mass fraction of 14.3% and a vapor density of 3.86 can be determined using the given information.

The molecular formula of the hydrocarbon can be calculated using the following steps:

1. Calculate the mass fraction of carbon and hydrogen in the hydrocarbon. 2. Determine the molar ratio of carbon to hydrogen. 3. Use the molar ratio to derive the molecular formula.

Calculation Steps

1. Calculate the Mass Fraction of Carbon and Hydrogen: - The mass fraction of carbon is 85.71% and the mass fraction of hydrogen is 14.29%.

2. Determine the Molar Ratio of Carbon to Hydrogen: - Using the mass fractions, the molar ratio of carbon to hydrogen can be calculated. - The molar mass of carbon is 12 g/mol and the molar mass of hydrogen is 1 g/mol. - By dividing the mass fraction of carbon by the molar mass of carbon and the mass fraction of hydrogen by the molar mass of hydrogen, the molar ratios can be obtained.

3. Derive the Molecular Formula: - Once the molar ratios are determined, the molecular formula of the hydrocarbon can be derived.

Conclusion

The molecular formula of the hydrocarbon with a hydrogen mass fraction of 14.3% and a vapor density of 3.86 is determined using the given information.