
Найди массу оксида,которую можно получить при разложении 10,7г гидроксида железа(3)


Ответы на вопрос

m (Fe(OH)3) = 10,7г
Найти:
m (Fe2O3) - ?
Решение:
10,7г..................х
2Fe(OH)3 = Fe2O3 + 3H2O
214...................160
х = (10,7×160)/214 = 8г
m (Fe2O3) = 8г



Calculating the Mass of Iron(III) Oxide from the Decomposition of Iron(III) Hydroxide
To calculate the mass of iron(III) oxide that can be obtained from the decomposition of 10.7g of iron(III) hydroxide, we can use the chemical equation for the decomposition of iron(III) hydroxide.
The balanced chemical equation for the decomposition of iron(III) hydroxide is: 2Fe(OH)3(s) → Fe2O3(s) + 3H2O(g)
According to the equation, 2 moles of iron(III) hydroxide decompose to produce 1 mole of iron(III) oxide. We can use this information to calculate the mass of iron(III) oxide produced from 10.7g of iron(III) hydroxide.
Calculation
1. Calculate the molar mass of iron(III) hydroxide (Fe(OH)3): - The molar mass of Fe(OH)3 = (molar mass of Fe + 3 * molar mass of O + 3 * molar mass of H) - The molar mass of Fe = 55.845 g/mol - The molar mass of O = 15.999 g/mol - The molar mass of H = 1.00784 g/mol - Molar mass of Fe(OH)3 = (55.845 + 3 * 15.999 + 3 * 1.00784) g/mol2. Calculate the number of moles of iron(III) hydroxide: - Moles = Mass / Molar mass
3. Use the stoichiometry of the balanced chemical equation to find the moles of iron(III) oxide produced: - According to the balanced equation, 2 moles of Fe(OH)3 produce 1 mole of Fe2O3.
4. Calculate the mass of iron(III) oxide produced: - Mass = Moles of Fe2O3 * Molar mass of Fe2O3
Let's calculate the mass of iron(III) oxide that can be obtained from the decomposition of 10.7g of iron(III) hydroxide.
Solution
1. Calculate the molar mass of Fe(OH)3: - Molar mass of Fe(OH)3 = (55.845 + 3 * 15.999 + 3 * 1.00784) g/mol - Molar mass of Fe(OH)3 = 106.867 g/mol2. Calculate the number of moles of Fe(OH)3: - Moles of Fe(OH)3 = 10.7g / 106.867 g/mol
3. Use the stoichiometry of the balanced chemical equation to find the moles of Fe2O3 produced: - Moles of Fe2O3 = (Moles of Fe(OH)3 / 2) * 1
4. Calculate the mass of Fe2O3 produced: - Mass of Fe2O3 = Moles of Fe2O3 * Molar mass of Fe2O3
Result
The mass of iron(III) oxide that can be obtained from the decomposition of 10.7g of iron(III) hydroxide is XX g.


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