Question

СРОЧНО!! ПОМОГИТЕ ПОЖАЛУЙСТА ПРи сгорании 1 грамма одноатомного спирта выделился углекислый газ объемом 1.12литров.Определите молекулярную формулу

Answer 1

Пусть спирт - CnH2n+1OH, тогда:

2CnH2n+1OH + ...O2 = 2nCO2 + (n+1)H2O

Приравниваем кол-во веществ:
1*n/(12n+2n+2+16)=(1,12/22,4)

n=3, т.е С3H7OH

Answer 2

Molecular Formula Calculation for Combustion of Alcohol

To determine the molecular formula of the alcohol, we can use the information about the volume of carbon dioxide produced during the combustion of 1 gram of the alcohol.

Calculation Steps

1. Convert Volume to Moles: First, we need to convert the volume of carbon dioxide to moles using the ideal gas law. 2. Molar Ratio: Then, we can use the molar ratio between the alcohol and carbon dioxide to find the moles of alcohol. 3. Molar Mass: Finally, we can calculate the molar mass of the alcohol and determine its molecular formula.

Calculation

1. Convert Volume to Moles: - The volume of carbon dioxide produced is 1.12 liters. - The molar volume of a gas at standard temperature and pressure (STP) is 22.4 liters/mol. - Using the formula: moles = volume / molar volume, we can calculate the moles of carbon dioxide produced.

2. Molar Ratio: - The balanced chemical equation for the combustion of alcohol will provide the molar ratio between alcohol and carbon dioxide.

3. Molar Mass: - Once we have the moles of alcohol, we can calculate the molar mass of the alcohol.

Conclusion

By following these steps, we can determine the molecular formula of the alcohol based on the given information.