Question

NH3+O2-->N2+H2O Надо подобрать коэффициенты методом электронного баланса

Answer 1

4NH3 + 3O2 = 2N2 + 6H2O

ОВР :   

O2 + 2H2O + 4e− = 4OH−

2NH3 + 6OH− − 6e− = N2 + 6H2O

Answer 2

Balancing the Chemical Equation NH3 + O2 -> N2 + H2O

To balance the chemical equation NH3 + O2 -> N2 + H2O using the method of electron balance, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's start by counting the number of atoms for each element on both sides of the equation:

On the left side (reactants): - Nitrogen (N): 1 atom - Hydrogen (H): 3 atoms - Oxygen (O): 2 atoms

On the right side (products): - Nitrogen (N): 2 atoms - Hydrogen (H): 2 atoms - Oxygen (O): 1 atom

To balance the equation, we need to adjust the coefficients in front of each compound to ensure that the number of atoms is the same on both sides.

Balancing the Nitrogen (N) Atoms

Since there is only one nitrogen atom on the left side and two nitrogen atoms on the right side, we need to balance the nitrogen atoms by placing a coefficient of 2 in front of NH3 on the left side:

2 NH3 + O2 -> N2 + H2O

Now, let's count the number of atoms for each element again:

On the left side (reactants): - Nitrogen (N): 2 atoms - Hydrogen (H): 6 atoms - Oxygen (O): 2 atoms

On the right side (products): - Nitrogen (N): 2 atoms - Hydrogen (H): 2 atoms - Oxygen (O): 1 atom

Balancing the Hydrogen (H) Atoms

Since there are 6 hydrogen atoms on the left side and only 2 hydrogen atoms on the right side, we need to balance the hydrogen atoms by placing a coefficient of 3 in front of H2O on the right side:

2 NH3 + O2 -> N2 + 3 H2O

Now, let's count the number of atoms for each element again:

On the left side (reactants): - Nitrogen (N): 2 atoms - Hydrogen (H): 6 atoms - Oxygen (O): 2 atoms

On the right side (products): - Nitrogen (N): 2 atoms - Hydrogen (H): 6 atoms - Oxygen (O): 6 atoms

Balancing the Oxygen (O) Atoms

Since there are 2 oxygen atoms on the left side and 6 oxygen atoms on the right side, we need to balance the oxygen atoms by placing a coefficient of 5/2 (or 2.5) in front of O2 on the left side:

2.5 O2 + 2 NH3 -> N2 + 3 H2O

Multiplying all the coefficients by 2 to eliminate the decimal:

5 O2 + 4 NH3 -> 2 N2 + 6 H2O

Now, let's count the number of atoms for each element again:

On the left side (reactants): - Nitrogen (N): 4 atoms - Hydrogen (H): 12 atoms - Oxygen (O): 10 atoms

On the right side (products): - Nitrogen (N): 4 atoms - Hydrogen (H): 12 atoms - Oxygen (O): 12 atoms

The equation is now balanced with the coefficients: 5 O2 + 4 NH3 -> 2 N2 + 6 H2O.

Please note that the coefficients in a balanced equation represent the ratio of moles, not the actual number of molecules.