Question

вычислите объём (н.у) хлора, который потребруется для вытеснения всего иода из 500г 15%-ного раствора иодида калия.

Answer 1

127г/моль*1моль=127г,22.4/x=127/75,х=22.4*127/75=5 л     Это решение а формулы и элементы напишишь я только что сам это решил тоже одно и тоже задали))))

Answer 2

Calculation of Chlorine Volume Required to Displace Iodine

To calculate the volume of chlorine (at standard temperature and pressure) required to displace all the iodine from a 500g 15% solution of potassium iodide, we need to use the balanced chemical equation for the reaction between chlorine and potassium iodide.

The balanced chemical equation for the reaction is: ``` Cl2 + 2KI -> 2KCl + I2 ```

From the equation, we can see that 1 mole of chlorine reacts with 2 moles of potassium iodide to produce 2 moles of potassium chloride and 1 mole of iodine.

To calculate the moles of iodine present in the 500g 15% solution of potassium iodide, we first need to determine the mass of iodine in the solution.

The mass of iodine in the solution can be calculated using the mass percent composition formula: ``` Mass of iodine = (Mass percent of iodine / 100) * Mass of solution ```

Given that the solution is 15% potassium iodide and the total mass of the solution is 500g, we can calculate the mass of iodine as follows: ``` Mass of iodine = (15 / 100) * 500g = 75g ```

Next, we need to calculate the number of moles of iodine using its molar mass. The molar mass of iodine (I2) is approximately 253.8 g/mol.

Number of moles of iodine = Mass of iodine / Molar mass of iodine ``` Number of moles of iodine = 75g / 253.8 g/mol ≈ 0.295 moles ```

Since 1 mole of chlorine reacts with 1 mole of iodine, we can conclude that we need 0.295 moles of chlorine to displace all the iodine.

To calculate the volume of chlorine gas at standard temperature and pressure (STP), we can use the ideal gas law equation: ``` PV = nRT ```

Where: P = pressure (at STP, pressure is 1 atm) V = volume n = number of moles of gas R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature (at STP, temperature is 273.15 K)

Rearranging the equation, we can solve for V: ``` V = (nRT) / P ```

Substituting the values into the equation: ``` V = (0.295 moles * 0.0821 L·atm/(mol·K) * 273.15 K) / 1 atm ```

Calculating the volume: ``` V ≈ 6.98 L ```

Therefore, approximately 6.98 liters of chlorine gas (at standard temperature and pressure) would be required to displace all the iodine from the 500g 15% solution of potassium iodide.

Please note that the above calculation assumes ideal conditions and does not take into account any potential side reactions or losses during the process.