Question

Разлагается 3,4 г аммиака, сколько г водорода образуется при этом

Answer 1

Масса (NH3) = 3,4 г
масса (H)- ? г
2NH3=3H2+N2
n(NH3)=3,4/17=0,2 моль
2n(NH3)=3n(H)=0,6 моль
масса(Н)=0,6*1=0,6 грамм 
Ответ:0,6 грамм

Answer 2

Calculation of Hydrogen Formation from the Decomposition of Ammonia

When 3.4 grams of ammonia decomposes, the amount of hydrogen formed can be calculated using the chemical equation for the decomposition of ammonia.

The balanced chemical equation for the decomposition of ammonia is:

2NH3 → 3H2 + N2

According to the stoichiometry of the reaction, 2 moles of ammonia decompose to produce 3 moles of hydrogen.

Using the molar mass of ammonia (NH3) and hydrogen (H2), we can calculate the amount of hydrogen formed when 3.4 grams of ammonia decomposes.

The molar mass of ammonia (NH3) is approximately 17.03 g/mol, and the molar mass of hydrogen (H2) is approximately 2.02 g/mol.

Using this information, we can calculate the amount of hydrogen formed when 3.4 grams of ammonia decomposes.