Question

Хватит ли 15 молекул кислорода для окисления 30 атомов железа до оксида железа 3

Answer 1

1   с п о с о б.
4Fe + 3O₂ =2 Fe₂O₃    это ТЕОРЕТИЧЕСКАЯ реакция, только для ответа на вопрос о соотношении атомов.
( Идут реакции   1) 3Fe + O₂ = F₃O₄ 
2) 4Fe₃O₄ + O₂ = 6Fe₂O₃)
составляем пропорцию 
4Fe    -----    3O₂
30 Fe -----     X  O₂
X = 3 * 30/4 = 22,5 молекул O₂
2   с п о с о б.
Окись Fe (III)   Fe₂O₃ 
составим пропорцию:
2 атома Fe     ----- 3 атома О
30 атомов Fe------ Х атомов О
Х = 3 *30/2 = 45 атомов O = 22,5 молекул О₂
Ответ: не хватит
  
Это соотношение для получения оксида железа (II)
2Fe + O₂ = 2FeO
2 атома Fe  ------- 1 молекула О₂
30 атомов Fe ------ У молекул О₂ 
У = 30*1/2 = 15 (молекул О₂)

Answer 2

Calculating Oxygen Molecules Required to Oxidize Iron to Iron(III) Oxide

To calculate the number of oxygen molecules required to oxidize 30 atoms of iron to iron(III) oxide, we can use the balanced chemical equation for the reaction. The balanced chemical equation for the oxidation of iron to iron(III) oxide is:

4Fe(s) + 3O2(g) → 2Fe2O3(s)

From the balanced equation, we can see that 3 moles of O2 are required to react with 4 moles of Fe to produce 2 moles of Fe2O3.

Now, let's calculate the number of moles of oxygen molecules required to oxidize 30 atoms of iron to iron(III) oxide.

Calculation

1. Calculate the moles of iron atoms: - Given: 30 atoms of iron - Moles of iron = 30 atoms / Avogadro's number - Moles of iron ≈ 30 / 6.022 x 10^23 - Moles of iron ≈ 4.977 x 10^-23 moles

2. Calculate the moles of oxygen molecules required: - From the balanced equation, 3 moles of O2 are required for 4 moles of Fe. - Moles of O2 required = (3/4) * moles of iron - Moles of O2 required ≈ (3/4) * 4.977 x 10^-23 - Moles of O2 required ≈ 3.733 x 10^-23 moles

Answer

To oxidize 30 atoms of iron to iron(III) oxide, approximately 3.733 x 10^-23 moles of oxygen molecules are required.

This calculation is based on the balanced chemical equation for the oxidation of iron to iron(III) oxide and the stoichiometry of the reaction.